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3 years ago

Two numbers total 31 and have a difference of 11. Find the two numbers

Mathematics

2 answers:

nexus9112 [7]3 years ago

8 0

Answer:

let 2 no. be x and y

x+y=31 ..... (1)

x-y=11 .........(2)

from (1)

x=31-y ..........(3)

putting (3) in (2)

31-y-y=11

-2y=11-31

-2y=-20

2y=20

y=10

Lostsunrise [7]3 years ago

5 0

31 -11 = 20
20 + 11 = 31
The Two numbers are 20 & 11

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3 years ago

How do I do this?? Help!

Shkiper50 [21]

Hi there!

In order to use the elimination method, you have to create one variable that has the same coefficient. This is to be able to eliminate one variable and have a one variable equation (which you can then solve).

In your case, we'll have the "x" have the same coefficient by multiplying the top equation by 4 and the bottom equation by 2 :

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In your case, you want to add both equation together which will give you :

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There you go! I really hope this helped, if there's anything just let me know! :)

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3 years ago

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Tan(A+45°) - tan(A-45°) =2sec2A

weeeeeb [17]

Answer:

$\tan(A + 45 \degree) - \tan(A - 45 \degree) \\ \\ = \frac{ \tan(A) + \tan(45 \degree) }{1 - \tan(A) \tan(45 \degree) } - \frac{ \tan(A) - \tan(45 \degree) }{1 + \tan(A) \tan(45 \degree) } \\ \\$

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3 years ago

The larger of two numbers is twice the smaller increased by five. Find the two numbers if three times the larger exceeds double

irina [24]

The larger number is 13 and smaller number is 4

<em><u>Solution:</u></em>

Let the larger number be "a"

Let the smaller number be "b"

<em><u>Given that larger of two numbers is twice the smaller increased by five</u></em>

larger number = twice the smaller increased by five

larger number = twice the smaller number + 5

a = 2b + 5 --- eqn 1

<em><u>Also given that three times the larger exceeds double the smaller by 31</u></em>

Here "exceeds" denotes addition and "times" denotes multiplication

"double" denotes being multiplied by 2

three times the larger number = double the smaller number + 31

3a = 2b + 31 ---- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "b"</u></em>

Substitute eqn 1 in eqn 2

3(2b + 5) = 2b + 31

6b + 15 = 2b + 31

6b - 2b = 31 - 15

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From eqn 1,

a = 2b + 5

a = 2(4) + 5

a = 8 + 5

Thus the larger number is 13 and smaller number is 4

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3 years ago