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ddd [48]
3 years ago
15

Marigold Corp. purchased a truck at the beginning of 2020 for $109700. The truck is estimated to have a salvage value of $4200 a

nd a useful life of 123000 miles. It was driven 22000 miles in 2020 and 30000 miles in 2021. What is the depreciation expense for 2020
Business
1 answer:
jeka57 [31]3 years ago
6 0

Answer:

the depreciation expense of the year 2020 is $18,870

Explanation:

The computation of the depreciation expense of the year 2020 is as follows:

= (Truck value - salvage value) ÷ (useful life) × (driven miles)

= ($109,700 - $4,200) ÷ (123,000 miles) × (22,000 miles)

= $18,870

Hence, the depreciation expense of the year 2020 is $18,870

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Suppose that the market demand curve for bean sprouts is given by P = 1,660 - 4Q, where P is the price and Q is total industry o
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Answer:

In equilibrium, total output by the two firms will be option e= 300.  

Q = q_{1} + q_{2}

Q = 100 + 200

Q = 300

Explanation:

Data Given:

Market Demand Curve = P = 1660-4Q

where, P = price and Q = total industry output

Each firm's marginal cost = $60 per unit of output

So, we know that Q =  q_{1} + q_{2}

where q_{} being the individual firm output.

Solution:

P = 1660-4Q

P = 1660- 4(q_{1} + q_{2})

P = 1660 - 4q_{1} - 4q_{2}

Including the marginal cost of firm 1 and multiplying the whole equation by q_{1}

Let's suppose new equation is X

X =  1660q_{1} - 4q_{1} ^{2} - 4q_{1}q_{2} - 60q_{1}

Taking the derivative w.r.t to q_{1}, we will get:

X^{'} = 1660 - 8q_{1} - 4q_{2} - 60 = 0

Making rearrangements into the equation:

8q_{1} + q_{2} = 1660 - 60

8q_{1} + q_{2} = 1600

Dividing the whole equation by 4

2q_{1} +q_{2} = 400

Solving for q_{1}

2q_{1} = 400 - q_{2}

q_{1} = 200 - 0.5 q_{2}  

Including the marginal cost of firm 1 and multiplying the whole equation by q_{2}

P = 1660 - 4q_{1} - 4q_{2}

Let's suppose new equation is Y

Y =  1660q_{2} - 4q_{1}q_{2} -4q_{2} ^{2} - 60q_{2}

Pugging in the value of q_{1}

Y =  1660q_{2} - 4q_{2}(200 - 0.5 q_{2}) -4q_{2} ^{2} - 60q_{2}

Y =  1660q_{2} - 800q_{2} +2q_{2} ^{2} -4q_{2} ^{2} - 60q_{2}

Y =  1600q_{2} - 800q_{2} -2q_{2} ^{2}

Taking the derivative w.r.t q_{2}

Y^{'} = 1600 - 800 - 4q_{2} = 0

Solving for q_{2}

4q_{2} = 800

q_{2} = 200

q_{1} = 200 - 0.5 q_{2}

Plugging in the value of q_{2} to get the value of q_{1}

q_{1} = 200 - 0.5 (200)

q_{1} = 200 - 100

q_{1} = 100

Q = q_{1} + q_{2}

Q = 100 + 200

Q = 300

Hence, in equilibrium, total output by the two firms will be option

e= 300.

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