Which statements are true about the polynomial function?

Como acho a classe de equivalência de 5/9 e 7/13

Brilliant_brown [7]

A) 5/9 = 10/18

b)7/13 = 14/26

4 0

3 years ago

Given the graph of a line y=−x. Write an equation of a line which is parallel and goes through the point (−8,2)

Savatey [412]

Answer:

The parallel line would be y = -x - 6

Step-by-step explanation:

In order to find the parallel line, we must first start with the slope. The slope of parallel lines must be equal. The first line has a slope of -1. Using this and the new point in slope intercept form, we can solve for the intercept.

y = mx + b

2 = -1(-8) + b

2 = 8 + b

-6 = b

Now we can model the equation using that slope and the intercept.

y = -x - 6

5 0

3 years ago

A simple random sample of size nequals=8181 is obtained from a population with mu equals 77μ=77 and sigma equals 27σ=27. (a) De

ivanzaharov [21]

Answer:

a) $P(\bar X>81.5)=1-0.933=0.067$

b) $P(\bar X$

c) $P(73.4$

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Let X the random variable that represent interest on this case, and for this case we know the distribution for X is given by:

$X \sim N(\mu=77,\sigma=27)$

And let $\bar X$ represent the sample mean, the distribution for the sample mean is given by:

$\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})$

On this case $\bar X \sim N(77,\frac{27}{\sqrt{81}})$

Part a

We want this probability:

$P(\bar X>81.5)=1-P(\bar X$

The best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

If we apply this formula to our probability we got this:

$P(\bar X >81.5)=1-P(Z$

$P(\bar X>81.5)=1-0.933=0.067$

Part b

We want this probability:

$P(\bar X\leq 69.5)$

If we apply the formula for the z score to our probability we got this:

$P(\bar X \leq 69.5)=P(Z\leq \frac{69.5-77}{\frac{27}{\sqrt{81}}})=P(Z$

$P(\bar X\leq 69.5)=0.0062$

Part c

We are interested on this probability

$P(73.4$

If we apply the Z score formula to our probability we got this:

$P(73.4$

$=P(\frac{73.4-77}{\frac{27}{\sqrt{81}}}$

And we can find this probability on this way:

$P(-1.2$

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

$P(-1.2$

3 0

4 years ago

What is the missing length????

ehidna [41]

The answer is B (20.2 ft)

7 0

4 years ago

Q # 5 please help to resolve

krok68 [10]

Answer: Second option: 8/21

Solution:
P(1) = (Number of times we get 1) / (Total number of results)

Number of times we get 1 = 8
Total number of results = 21

P(1)=8/21

4 0

4 years ago

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