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dezoksy [38]
3 years ago
11

Como acho a classe de equivalência de 5/9 e 7/13

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
4 0

A) 5/9 = 10/18

b)7/13 = 14/26

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Plz help this question is hard for me.
Burka [1]
The Answer is : r = -26

7 0
4 years ago
Read 2 more answers
Look at the image attached below.
SSSSS [86.1K]

Step-by-step explanation:

<u>Step 1:  Subtract the first part</u>

<u />1\frac{1}{2} - \frac{1}{4}

\frac{3}{2} - \frac{1}{4}

\frac{6}{4}-\frac{1}{4}

\frac{5}{4}

<u>Step 2:  Multiply both to get how much the brother drank</u>

<u />\frac{5}{4} * \frac{2}{5}

\frac{2}{4}

\frac{1}{2} \ L

Answer:  1/2 Liters

4 0
3 years ago
Read 2 more answers
How do I solve for c and d
tankabanditka [31]
For c using proportionality of corresponding sides you can writing 

(3c+4)       9
--------- = -------
    20         15

(3c+4)       3
---------- = ------    cross multiple 
    20          5

5(3c+4) = 20*3   divide both sides by 5

3c+4=4*3

3c+4=12

3c = 8

c = 8/3

for d you can writing 

(2d-3)       9
--------- = ------
   12          15

(2d-3)       3
--------- = -------   cross multiple 
   12          5

5(2d-3) = 12*3

10d -15 = 36

10d = 51

d = 51/10

d = 5,1

hope helped 

6 0
3 years ago
For the function f(x)=3xsquared- 2x+5 find f(1) f(-2) and f(a)
Oksanka [162]
f(x)=3x^2-2x+5\\\\&#10;f(1):\ \ Substitude\ 1 \ as\ x\ into\ function:\\&#10;f(1)=3*1^2-2*1+5=3-2+5=\textbf{6}\\\\&#10;f(-2)\ \ Substitude\ x=-2\\&#10;f(-2)=3*(-2)^2-2*(-2)+5=3*4+4+5=12+4+5=\textbf{21}\\\\&#10;f(a)\ \ substitude\ x=a\\&#10;f(a)=\underline{3a^2-2a+5}
4 0
4 years ago
I need the answer pls
AleksAgata [21]

the answer is 32.........

8 0
3 years ago
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