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3 years ago

What is the value of the expression? 53/5+7/10−22/3

1 answer:

6 0

119/30 or 3.96 or 3 29/30

Explanation:
First write all numerators above the least common denominator (in this case 30)

Then calculate the sum or difference

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Pschological tests are often used to determine the hostility levels in people. High scores on the HLT pschological test correspo

algol13

Answer: the correct answer is we are 95% confident that there is no statistically significant difference in the mean treatment methods for hostility.

Step-by-step explanation:

1) Test for the equality of variances in the two groups to choose the appropriate t-test.

H0: σ (1)^2 = σ (2)^2

Ha: σ (1)^2 ≠ σ (2)^2

Larger variance = 64

Smaller variance = 49

F = 1.30612

Degrees of freedom 15 and 9

Critical F from the table (with alpha=0.05) = 2.58

Calculated F is smaller than critical F, so we use the pooled variance t-test.

Sample 1 size 7

Sample 2 size 8

Sample 1 mean 79

Sample 2 mean 84

Sample 1 S.D. 7

Sample 2 S.D. 8

Pooled S.D = [(n1-1)s1^2+(n2-1)s2^2]/(n1+n2-2)

Pooled variance s = [(6)(49)+(7)(64))] / (13) = (294+448)/13=742/13=57.076923

Pooled variance s^2 = 57.076923

Standard error of difference in means = sqrt(1/n1+1/n2) times sqrt(s^2)

Standard error of difference in means = (0.517549)(7.554927) = 3.910046 (denominator of t)

Confidence interval = (mean1-mean2) +/- t SE

t is the critical t with 24 degrees of freedom = 2.056

(79 - 84) +/- (2.056) (3.910046)

= (-13.04, 3.04)

Interval encloses 0

We are 95% confident that there is no statistically significant difference in the mean treatment methods for hostility.

4 0

3 years ago

A company studied the number of lost-time accidents occurring at its Brownsville, Texas, plant. Historical records show that 20%

zhuklara [117]

Answer:

a. 5% of the employees will experience lost-time accidents in both years

b. 24% of the employees will suffer at least one lost-time accident over the two-year period

Step-by-step explanation:

a. What percentage of the employees will experience lost-time accidents in both years?

20% last year, of those who suffered last year, 25% during this year. So

$p = 0.2*0.25 = 0.05$

5% of the employees will experience lost-time accidents in both years.

b. What percentage of the employees will suffer at least one lost-time accident over the two-year period?

5% during the two years.

10% during the current year. 25% of employees who had lost-time accidents last year will experience a lost-time accident during the current year.

So the 10% is composed of 5% during both years(25% of 20%) and 5% of the 80% who did not suffer during the first year.

First year yes, not on the second.

75% of 20%. So, total:

$0.05 + 0.05*0.8 + 0.75*0.2 = 0.24$

24% of the employees will suffer at least one lost-time accident over the two-year period

3 0

3 years ago

There are 312 cards in 6 decks of playing cards . IF YOU HAVE TIME PLEASE HELP ON THE OTHERS QUESTIONS BELOW IN THE PICTURES ! (

shepuryov [24]

To figure out how many cards are in each deck, divide 312 by 6. That comes out to a quotient of 52. That means there are 52 cards in each deck.

#5, the way to figure out which is the better deal, is to multiply the 2 package by the 5 package (note, DO NOT multiply the prices, only how many games they hold) that comes out to 10. So, what you do know is multiply the 2 games price by 5.

$11.98 * 5 = $59.9

Do the same with the 5 package, except multiply it by 2.

$24.95 * 2 = $49.9

Now, with these 2 answers you can tell that the 5 game package is $10 cheaper than the 2 game package, even though you are getting the same amount of games.

Hope this helps a little!

4 0

3 years ago

Hii pretty human, could pls help meeeee :((((((

Butoxors [25]

i'm really good at all kinds of math, but this doesn't make any sense.

7 0

2 years ago

Read 2 more answers

What is the value of the expression below 2,816 x 7

Ad libitum [116K]

Answer:

c. 19,712

Step-by-step explanation:

2,816 * 7 = 19,712

7 0

3 years ago