Given: MO−→− bisects ∠LMN m∠LMO = 6x−20 m∠NMO = 2x+36 Solve for x and find m∠LMN.
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Answer:
<h2>C.</h2>Step-by-step explanation:
<, > - open circle
≤, ≥ - solid circle
<, ≤ - draw to the left
>, ≥ - draw to the right
Using the normal distribution, it is found that 0.0329 = 3.29% of the population are considered to be potential leaders.
In a <em>normal distribution</em> with mean and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem:
- The mean is of 550, hence
.
- The standard deviation is of 125, hence
.
The proportion of the population considered to be potential leaders is <u>1 subtracted by the p-value of Z when X = 780</u>, hence:
has a p-value of 0.9671.
1 - 0.9671 = 0.0329
0.0329 = 3.29% of the population are considered to be potential leaders.
To learn more about the normal distribution, you can take a look at brainly.com/question/24663213