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3 years ago

What's the answer plz help 5 15 9

Mathematics

2 answers:

Natali [406]3 years ago

4 0

If you are asking what is 5+15+9 it’s 29 if you are asking what’s 5-15-9 it’s -19

Montano1993 [528]3 years ago

3 0

I’m confused, what is the question?

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Please help! time sensitive.

Ronch [10]

Answer:

true

Step-

when you divide fractions you have to keep change flip

7 0

3 years ago

Read 2 more answers

Find the solution of the given initial value problem. ty' + 2y = sin t, y π 2 = 9, t > 0 y(t) =

Helen [10]

For the ODE

$ty'+2y=\sin t$

multiply both sides by t so that the left side can be condensed into the derivative of a product:

$t^2y'+2ty=t\sin t$

$\implies(t^2y)'=t\sin t$

Integrate both sides with respect to t :

$t^2y=\displaystyle\int t\sin t\,\mathrm dt=\sin t-t\cos t+C$

Divide both sides by $t^2$ to solve for y :

$y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac C{t^2}$

Now use the initial condition to solve for C :

$y\left(\dfrac\pi2\right)=9\implies9=\dfrac{\sin\frac\pi2}{\frac{\pi^2}4}-\dfrac{\cos\frac\pi2}{\frac\pi2}+\dfrac C{\frac{\pi^2}4}$

$\implies9=\dfrac4{\pi^2}(1+C)$

$\implies C=\dfrac{9\pi^2}4-1$

So the particular solution to the IVP is

$y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac{\frac{9\pi^2}4-1}{t^2}$

$y(t)=\dfrac{4\sin t-4t\cos t+9\pi^2-4}{4t^2}$

6 0

2 years ago

The number on top of a fraction is called the

sineoko [7]

Hello!

The top number of a fraction is called the numerator

Hope this helps!

3 0

3 years ago

Read 2 more answers

A party planner is preparing gift bags for an event. She has purchased a large box of individually wrapped chocolates to divide

liubo4ka [24]

Chocolates per bag is the correct answer

7 0

3 years ago

I need help with these two trigonometry problems.

Ymorist [56]

Answer:

Step-by-step explanation:

For 5 we need to use sine law.

The thing about sine law is that we need to look at the triangle sides that are in front of the angles.

In this case: <B = 30°

the triangle side that is in front of this angle is AC which is 4 cm.

Then we got <C = 61°, and the triangle side in front of it is AB, which is what we need to find.

According to sine law:

$\frac{sin B}{AC} = \frac{sin C}{AB}$

$\frac{sin 30}{4} = \frac{sin 61}{AB}$

Notice that you need to be consistent. If you start writing that the angle is in the numerator, it needs to be in the numerator on the other side of the equation.

Solving it would give us:

(AB )(sin 30) = (sin 61)(4)

AB = 6.9969 cm

to the nearest tenth it's 7.0 cm

Question 6:

Wow it's pretty crowded, but they probably want us to use sine law as well. Let's write what we know:

<C = 12°

<B = 107°

AB = 21 yd

AC = ?

Apply it to the formula: sin(angle) / the triangle side in front of it.

$\frac{sin 12}{21} = \frac{sin 107}{AC}\\$

(sin 107)(21) = (sin 12)(AC)

AC = 96.59

to the nearest tenth AC = 96.6 yd

8 0

2 years ago