<em><u>Any integer (not a fraction) is divisible by 1
</u></em>
<em><u></u></em>
<em><u>The sum of the digits is divisible by 3
</u></em>
<em><u></u></em>
<em><u>The last 2 digits are divisible by 4
</u></em>
<em><u /></em>
<em><u>The last digit is 0 or 5
</u></em>
<em><u></u></em>
<em><u>Is even and is divisible by 3 (it passes both the 2 rule and 3 rule above)
</u></em>
<em><u></u></em>
<em><u>Double the last digit and subtract it from a number made by the other digits. The result must be divisible by 7. (We can apply this rule to that answer again)
</u></em>
<em><u></u></em>
<em><u>The last three digits are divisible by 8
</u></em>
<em><u></u></em>
<em><u>The sum of the digits is divisible by 9
</u></em>
<em><u></u></em>
<em><u>The number ends in 0
</u></em>
<em><u></u></em>
<em><u>Add and subtract digits in an alternating pattern (add digit, subtract next digit, add next digit, etc). Then check if that answer is divisible by 11.
</u></em>
<em><u></u></em>
<em><u>The number is divisible by both 3 and 4 (it passes both the 3 rule and 4 rule above)
</u></em>
