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3 years ago

6

Hi! Can somebody please help?

1 answer:

dezoksy [38]3 years ago

7 0

Answer:

Diagram A will reach the top first.

Explanation:

If it is going straight, it will go slower. The higher the movement speed the faster it is. Hope this helps!

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Item 4 A student conducts an experiment to determine how the temperature of water affects the time for sugar to dissolve. In eac

expeople1 [14]

Answer:

The Answer is C. the student changed too many variables.

Explanation:

For the quiz in K12

3 0

3 years ago

What are the sign and magnitude in coulomb's of a point charge that produces a potential of -1.50 V at a distance of 2.00 mm

Charra [1.4K]

Answer:

The sign of the charge is negative

The magnitude of the charge is 3.33 x 10⁻¹³ C

Explanation:

Given;

potential difference, V = -1.5 V

distance of the point charge, r = 2 mm = 2 x 10⁻³ m

The magnitude of the charge is calculated as follows;

$V = \frac{kq}{r} \\\\q = \frac{Vr}{k} \\\\where;\\\\k \ is \ coulomb's \ constant = 9\times 10^9 \ Nm^2/C^2\\\\q = \frac{-1.5 \times 2\times 10^{-3}}{9\times 10^9 } \\\\q = -3.33 \times 10^{-13} \ C\\\\Magnitude \ of \ the\ charge, q = 3.33 \times 10^{-13} \ C$

8 0

3 years ago

A system in which only one particle can move has the potential energy shown in (figure 1). Suppose u1 = 60 j. What is the y-comp

marta [7]

The y-component of the force on the particle at the given position is 120 N.

<h3>Electric force on the particle</h3>

The electric force on the particle is determined by applying Coulomb's law and work-energy theorem as shown below;

Fd = W

Where;

F is the applied force
d is the distance
W is potential

F = W/d

F = 60/0.5

F = 120 N

Thus, the y-component of the force on the particle at the given position is 120 N.

Learn more about electric force here: brainly.com/question/20880591

3 0

2 years ago

The moon has a mass of 7.34 . 102 kg and a radius of 1.74 . 106 meters. If you have a mass of 66 kg,

Ierofanga [76]

Answer:

$F=1.06\times 10^{-18}\ N$

Explanation:

Given that,

Mass of the Moon, $M=7.34\times 10^2\ kg$

Mass of the person, m = 66 kg

The radius of Moon, $r=1.74\times 10^6\ m$

We need to find the force between the person and the Moon. The formula for the gravitational force is given by :

$F=G\dfrac{Mm}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{7.34\times 10^2\times 66}{(1.74\times 10^6)^2}\\\\=1.06\times 10^{-18}\ N$

So, the required force is $1.06\times 10^{-18}\ N$ .

3 0

3 years ago

Which of the following would most likely happen if water did not form hydrogen bonds?

Trava [24]

Option C is the correct answer

6 0

4 years ago