If we have 2 coordinates say: (x1,y1) and (x2,y2)

Then the formula for the midpoint is:

((x1+x2)/2,(y1+y2)/2)

And the formula for the distance is:

Sqrt((x2-x1)^2+(y2-y1)^2)

So here we have (-1,-4) and (-7,4)

The midpoint is:

((-1+-7)/2,(-4+4)/2) = (-8/2,0/2) = (-4,0)

The distance is:

Sqrt((-7- -1)^2+(4- -4)^2)
= sqrt((-6^2)+(8^2))
=sqrt(36+64)
=sqrt(100)
=10

6 0

3 years ago

what is the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube

Dmitrij [34]

Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then

$\frac{99}{2} (2x+98)=p^3 \\ \\ 99x+4,851=p^3\\ \\ \Rightarrow x=\frac{p^3-4,851}{99}$

By substitution, we have that $p=33$ and $x=314$ .

Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>

3 0

4 years ago

Solve each equation below for x show all work and check your answer by substituting it back into the equation and verifying that

Viefleur [7K]

Answer:

The equations are

(a) x/3 = 6

(b) (5x + 9)/2 = 12

(d) 5/x = 20/8

The answers to the question are

(a) x = 18

(b) x = 3

(d) x = 2

Step-by-step explanation:

(a) x/3 = 6

Therefore x = 3×6 = 18

x =18

Substituting the value of x in the above equation, we have

18/6 = 3 verified

(b) (5x + 9)/2 = 12

Multiplying both sides by 2 gives

(5x + 9)/2 × 2 = 12×2 = 24

5x + 9 = 24 or x = (24-9)/5 = 3

Substituting the value of x in the above equation, we have

(5×3 + 9)/2 = 24/2 = 12 verified

x = 3

Multiplying both sides by 4, we have

x/4×4 = 9/6×4 = 6

x = 6

Substituting the value of x in the above equation, we have

(6/4 = 9/6 = 3/2 verified

(d) 5/x = 20/8

Inverting both equations, we have

x/5 = 8/20

Multiplying both sides by 20 we have x/5 × 20 = 8/20 × 20 or 4x = 8 and x = 2

Substituting the value of x in the original equation, we have

2/5 = 2/5 = 8/20 verified

x = 2

6 0

3 years ago