Question

A box contains four red balls and eight black balls. Two balls are randomly chosen from the box, and are not replaced. Let event B be choosing a black ball first and event R be choosing a red ball second. What are the following probabilities? P(B) = ✔ 8/12 P(R | B) = ✔ 4/11 P(B ∩ R) = The probability that the first ball chosen is black and the second ball chosen is red is about percent

Answer 1

Answer:

8/12

4/11

8/33

24%

Step-by-step explanation:

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Answer 2

Answer:

P(B) = 8/12

P(R | B) = 4/11

P(B ∩ R) = 8/33

The probability that the first ball chosen is black and the second ball chosen is red is about  24 percent.

Step-by-step explanation:

I just got it right on edge 2020. Good luck with school!!