All categories

3 years ago

7 cm

Mathematics

1 answer:

arlik [135]3 years ago

6 0

Answer:

AT=48.9

Step-by-step explanation:

Formula:

step 1; Aʟ = P ʙᴀsᴇ × Ap

step 2; Aᴛ = Aʟ + Aʙᴀsᴇ

Ap= 7cm

Abase= 6.9cm² P️= a + b+ c

length side️=4cm

AL = (4+4+4) × 7

= 12 × 7

= 84 ÷2

AL = 42

AT = AL + Abase

= 42 + 6.9

AT = 48.9 cm

You might be interested in

Please can someone answer this question quickly please Thanks

inessss [21]

Answer:

C. 5/7

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Given g(x)=2x-1, solve for x when g(x)=3.

SashulF [63]

Answer:g(x)=2(3)+1=6+1=7

Step-by-step explanation:7

7 0

3 years ago

Read 2 more answers

In order for you to answer the question correctly, please use the following image down below:

adell [148]

Answer:

Step-by-step explanation:

24^2 = (12)(12+x)

576 = 144 + 12x

432 = 12x

36 = x

7 0

3 years ago

Figure A is dilated by a scale factor of 1 to form Figure B.

son4ous [18]

Answer:

C. 8 inches

Step-by-step explanation:

Note. The original question is attached.

Solution:

Scale factor is 1/2 and the corresponding side has a length of 16 inches.

The value of x is:

x = 1/2*16 = 8 inches

Correct option is C

6 0

3 years ago

Solve the given differential equation by using an appropriate substitution. The DE is a Bernoulli equation.

Mama L [17]

Multiplying both sides by $y^2$ gives

$xy^2\dfrac{\mathrm dy}{\mathrm dx}+y^3=1$

so that substituting $v=y^3$ and hence $\frac{\mathrm dv}{\mathrm dv}=3y^2\frac{\mathrm dy}{\mathrm dx}$ gives the linear ODE,

$\dfrac x3\dfrac{\mathrm dv}{\mathrm dx}+v=1$

Now multiply both sides by $3x^2$ to get

$x^3\dfrac{\mathrm dv}{\mathrm dx}+3x^2v=3x^2$

so that the left side condenses into the derivative of a product.

$\dfrac{\mathrm d}{\mathrm dx}[x^3v]=3x^2$

Integrate both sides, then solve for $v$ , then for $y$ :

$x^3v=\displaystyle\int3x^2\,\mathrm dx$

$x^3v=x^3+C$

$v=1+\dfrac C{x^3}$

$y^3=1+\dfrac C{x^3}$

$\boxed{y=\sqrt[3]{1+\dfrac C{x^3}}}$

6 0

3 years ago