Answer:
![\frac{\sqrt[3]{5} }{3x}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%7D%7B3x%7D)
Step-by-step explanation:
Ok, let's do this step by step....
![\sqrt[3]{\frac{10x^{5} }{54x^{8} } }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B10x%5E%7B5%7D%20%7D%7B54x%5E%7B8%7D%20%7D%20%7D)
Let's first simplify the x's:
![\sqrt[3]{\frac{10}{54x^{3} } }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B10%7D%7B54x%5E%7B3%7D%20%7D%20%7D)
Then we breakdown the 54 as 2 * 27 then simplify with the 10 above.
![\sqrt[3]{\frac{10}{2 * 27x^{3} } } = \sqrt[3]{\frac{5}{27x^{3} } }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B10%7D%7B2%20%2A%2027x%5E%7B3%7D%20%7D%20%7D%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B5%7D%7B27x%5E%7B3%7D%20%7D%20%7D)
Now, we can rewrite this as the following and solve the bottom part:
![\frac{\sqrt[3]{5} }{\sqrt[3]{27x^{3} } } = \frac{\sqrt[3]{5} }{3 \sqrt[3]{x^{3} } } = \frac{\sqrt[3]{5} }{3x}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%7D%7B%5Csqrt%5B3%5D%7B27x%5E%7B3%7D%20%7D%20%7D%20%3D%20%5Cfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%7D%7B3%20%5Csqrt%5B3%5D%7Bx%5E%7B3%7D%20%7D%20%7D%20%3D%20%5Cfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%7D%7B3x%7D)
The solution is
Answer:
a the answer is a
Step-by-step explanation:
Answer: I think you multiply the fraction together
Step-by-step explanation:
It is given that batteries come in a packs of 4. It means in each pack there are 4 batteries.
Joe used 58 batteries . So to find the total number of packets of batteries joe has to open is
Number of batteries used / Total number of batteries in each packet
= 58 / 4
= 14.5
The number of battery can not be in decimal. So we will round the answer to integer. If we round it to 14 it means 14 packets. But in 14 packets there are 14*4 = 56 batteries .
But we know that Joe used 58 batteries. So we will round the final answer to 15.
It means Joe has to open 15 packets of batteries.
Answer:
Height of the silo = 18 feet.
Step-by-step explanation:
From the figure attached BC is the length of the silo and the height of the farmer is 5 ft.
Farmer is standing at 8 ft distance from the silo.
From triangle AEC,
tan(∠CAE) = CE/AE=5/8
m(∠CAE) = tan-1 (5/8)
= 32°
m∠BAE = 90° - 32° = 58°
From the triangle ABE,
tan58° = BE/AE
BE = 8tan58°
BE = 12.8 ft
Total height of the silo = BE + EC
= 12.8 + 5
= 17.8
≈ 18 ft
Therefore, the total height of the silo is 18 ft.
