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Dmitriy789 [7]
3 years ago
6

Find the domain and range of the relation: {(–20, 11), (6, –8), (1, –20), (–13, 13)}

Mathematics
1 answer:
user100 [1]3 years ago
4 0

Answer:

D: {-20, -13, 1, 6}

R: {-20, -8, 11, 13}

Step-by-step explanation:

Given the relation, {(–20, 11), (6, –8), (1, –20), (–13, 13)}, all x-values (inputs) make up the domain of the relation while all y-values make up the range of the relation.

Therefore:

Domain: {-20, -13, 1, 6}

Range: {-20, -8, 11, 13}

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I'll give 50 points and brainliest to anyone who gives the best answer and explanation! These problems are confusing to me and a
Brut [27]

Answer:

<h2>(-3,8)</h2><h2>Or</h2><h2>x=-3 and y=8</h2>

Step-by-step explanation:

5 0
3 years ago
a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade
son4ous [18]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

P(at least 1 dull blade)=1-(\frac{38}{48}* \frac{37}{47} *\frac{36}{46}*\frac{35}{45}*\frac{34}{44})

P(at least 1 dull blade)=1-0.2931

P(at least 1 dull blade)=0.7068

5 0
3 years ago
Line A has an equation of y=-2/5x + 3. What is the slope of a line perpendicular
Nat2105 [25]

Answer:

\frac{5}{2}

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - \frac{2}{5} x + 3 ← is in slope- intercept form

with slope m = - \frac{2}{5}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{-\frac{2}{5} } = \frac{5}{2}

5 0
3 years ago
$3 is what percent of $4?
ozzi

Answer:

The answer is 3/4 = 75%

Step-by-step explanation:

3/4 = 75%

It is: 3/4 = 75%

4 0
3 years ago
Sofia, who lives in chicago, knits and sells alpaca-wool scarves. she spends 15 hours knitting one scarf. maria, who also knits,
erma4kov [3.2K]
A producer is said to have an absolute advantage over another producer when he required less amount of input to produce the same good compared to the other producer.

While a producer is said to have a comparative advantage over another producer when he produces his goods at a lesser opportunity cost compared to the other produer.

Here, time is one of the inputs used in production and Maria produces a scarf at a lesser time compared to Sofia. Thus, Maria has an absolute advantage over Maria in the production of scarves.

Therefore, the true statement is "<span>Maria has an absolute advantage over Sofia".</span>
5 0
3 years ago
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