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likoan [24]
3 years ago
9

H(x)=4x+4 find h(3b)

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
4 0

Answer:

h(3b)=12b+4

another answer

h(3b)=4(3b+1)

Step-by-step explanation:

h(x)=4x+4

h(3b)=4(3b)+4

h(3b)=12b+4

if need to simplify..then:

h(3b)=4(3b+1)

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A gardener planted some seedlings at equal distances apart along a straight road. The 3rd seedling and the 5th seedling were 9/1
ratelena [41]

Answer:

Answer:

17 seedlings

Step-by-step explanation:

Given;

The seedlings are at an equal distance in a straight line.

Distance between 3rd seedling and 5th seedling = 9/10 m

So, distance between 3rd seedling and 4th seedling = 9/10 ÷ 2 = 9/20 m

So, the distance between two seedlings in a line = 9/20 m

The given distance between 2nd seedling and the last seedling = 6 3/4 m = 27/4 m

8 0
2 years ago
plsss help with these math questions i will give brainliest to the best and clear answer that has an explanation!!!
erma4kov [3.2K]

For problem one she starts off earning 10.24 dollars per hour. She receives a raise of 1.60 dollars. So first you have to add both 10.24 and 1.60 together to find out how much more she is payed. 10.24+1.60=12.04. She works 22.25 hours. It would take forever to add 12.04 22 and a quarter times so you multiply them. 12.04*22.25=267.89. So she would earn 267.89 dollars from working 22.25 hours.

For problem two you would start off by dividing 3/4 (the amount of pizza) by 5 (the five people) because when you do this it will give you the equal amount of pizza that each person can have. You get 0.15 which is equal to 3/20. So each person will get 3/20 of the 3/4 of the pizza that are left. (To simplify it the answer is 3/20) you can check your work by doing 3*5 which is 15. Make this the numerator and it’s 15/20. 15/20=3/4.

For the third problem you start off by putting aside the .25 of an ounce. Take the 3 ounces and multiply it by the cost per ounce 3.56. 3*3.56=10.68. Now that you have figured out how much 3 ounces cost out that aside. Now for the .25 of an ounce. Since .25 goes into one four times you do 3.56/4. It’s 0.89. This is how much it costs per .25 of an ounce. After that you add 10.68+0.89. It’s 11.57. To finish the problem you have to subtract 11.57 from 20 dollars. 20.00-11.57=8.43. The teacher receives $8.43 in change.

7 0
2 years ago
Which of the following angles are supplementary to angle a? Select all that apply.
GuDViN [60]

Answer:

c is the supplement angle

3 0
2 years ago
Put them in order from least to greatest:<br> 9.5 9.66 9.662 9.551 9 9.59 9.626
Fiesta28 [93]

Answer:

9, 9.5,9.551,9.59,9.626,9.66,9.662

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Report Error Suppose $P(x)$ is a polynomial of smallest possible degree such that: $\bullet$ $P(x)$ has rational coefficients $\
motikmotik

Answer:

We want a polynomial of smallest degree with rational coefficients with zeros in \sqrt{7}, 1 - \sqrt{6} and -3. The last root gives us the factor (x+3). Hence, our polynomial is

P(x) =(x+3)q(x)

where q is a polynomial with rational coefficients and roots \sqrt{7} and 1 - \sqrt{6}. The root \sqrt{7} gives us a factor x-\sqrt{7}, but in order to obtain rational coefficients we must consider the factor x^2-7.

An analogue idea works with 1 - \sqrt{6}. For convenience write  x - 1 + \sqrt{6} = ( x - 1) + \sqrt{6}. This gives the factor (x-1)^2-6. Hence,

P(x) = (x+3)(x^2-7)((x-1)^2-6)=x^5+x^4-18x^3-22x^2+77x+105

Notice that P(-1)=24. So, in order to satisfy the last condition we divide by 3 the whole polynomial, without altering its roots. Finally, the wanted polynomial is

P(x) =(1/3)x^5+(1/3)x^4-6x^3-(22/3)x^2+(77/3)x+35

Step-by-step explanation:

We must have present that any polynomial it's determined by its roots up to a constant factor. But here we have irrational ones, in order to eliminate the irrational coefficients that a factor of the type x-\sqrt7 will introduce in the expression, we need to multiply by its conjugate x+\sqrt7. Hence, we will obtain x^2-7 that have rational coefficients. Finally, the last condition is given with the intention to fix the constant factor. Usually it is enough to evaluate in the point and obtain the necessary factor.

4 0
2 years ago
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