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Alex Ar [27]
3 years ago
7

Please help and show working outs of the screenshot attached

Mathematics
1 answer:
Degger [83]3 years ago
6 0

Answer:

Hey, do you know how to screenshot images? There is also a website for Brainly if needed

Step-by-step explanation:

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A wheel on a piece of machinery makes one revolution every minute (60 seconds.) How many degrees does it move in 10 seconds?
solmaris [256]

Answer:

It moves 6 degrees a second that means it moves 60 degrees in 10 seconds.

Step-by-step explanation:

360/60=6

6x10=60.

360 is how many degrees there are in a second and 60 seconds in a minutes.

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Is a ice cube a polygon? why or why not?
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A Polygon is a two dimensional figure that can be  drawn on a flat surface.A cube is a three dimensional figure that can be sculpted in three dimensions but can only have projections of it drawn on a flat surface.So a cube is not a polygon.
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John's fishing boat caught 2735 lbs of fish. They put them into boxes of 92 lbs each. About how many boxes did they need?
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Can you help me to solve this
stealth61 [152]

Answer:

\text{Triangle 1:}\\\\x=30\sqrt{2},\\\\\text{Triangle 2:}\\x\approx 36.18,\\?\approx12.37

Step-by-step explanation:

*Notes (clarified by the person who asked this question):

-The triangle on the right has a right angle (angle that appears to be a right angle is a right angle)

-The bottom side of the right triangle is marked with a question mark (?)

<u>Triangle 1 (triangle on left):</u>

Special triangles:

In all 45-45-90 triangles, the ratio of the sides is x:x:x\sqrt{2}, where x\sqrt{2} is the hypotenuse of the triangle. Since one of the legs is marked as 30, the hypotenuse must be \boxed{30\sqrt{2}}

It's also possible to use a variety of trigonometry to solve this problem. Basic trig for right triangles is applicable and may be the simplest:

\cos 45^{\circ}=\frac{30}{x},\\x=\frac{30}{\cos 45^{\circ}}=\frac{30}{\frac{\sqrt{2}}{2}}=30\cdot \frac{2}{\sqrt{2}}=\frac{60}{\sqrt{2}}=\frac{60\cdot\sqrt{2}}{\sqrt{2}\cdot \sqrt{2}}=\frac{60\sqrt{2}}{2}=\boxed{30\sqrt{2}}\\

<u>Triangle 2 (triangle on right):</u>

We can use basic trig for right triangles to set up the following equations:

\cos 20^{\circ}=\frac{34}{x},\\x=\frac{34}{\cos 20^{\circ}}\approx \boxed{36.18},

\tan 20^{\circ}=\frac{?}{34},\\?=34\tan 20^{\circ}\approx \boxed{12.37}

We can verify these answers using the Pythagorean theorem. The Pythagorean theorem states that in all right triangles, the following must be true:

a^2+b^2=c^2, where c is the hypotenuse of the triangle and a and b are two legs of the triangle.

Verify 34^2+(34\tan20^{\circ})^2=\left(\frac{34}{\cos20^{\circ}}\right)^2\:\checkmark

3 0
3 years ago
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