Let theta = A... Since I got no theta in my phone's keyboard
CotA /cosAsecA
Buh we all know cotA=1/tanA.....which can also be rewritten as cosA/sinA.... (thus the reciprocative Form of sinA/cosA)
SecA=1/cosA
Therefore
1/tanA ÷cosAx1/cosA
1/tanA ÷cosA/cosA
CosA/cosA=1
1/tan A÷1
Hence =cosA/sinA
S = 3T - 4
S = 23
23 = 3T - 4
23 + 4 = 3T
27 = 3T
27/3 = T
9 = T......so Travis's rope is 9 ft
Area of ∆=1/2bh
80yd^2=1/2(b)(10yd)
80yd^2=5yd(b)
80yd^2÷5yd=b
16yd=b
<h3>
Equation Step by Step</h3>
sin(4(3.141593^3)+3.141593^4)
sin((4)(31.006277)+3.141593^4)
sin(124.025107+3.1415934)
in(124.025107+97.409091)
sin(221.434198)
=0.998844
Tbh, might be wrong on this one. I'm on the road so didn't double-check my answer.
Answer:
Hey there!
First we find the slope: -3-0/10-4, or -3/6. That makes the slope -1/2.
Using point slope form we have-
y-0=-1/2(x-4)
y=-1/2x+2
Let me know if this helps, or if you need any more help :)