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3 years ago

Slopes of parallel lines are

Mathematics

1 answer:

KatRina [158]3 years ago

6 0

Answer:

the same as the original equation

Step-by-step explanation:

Since they don't intersect the slope is the same

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Consider the functions p and q.

xz_007 [3.2K]

Answer:

q= -1x

coordinates of p are .5, 2

Step-by-step explanation:

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2 years ago

How do I give brainlist?

Fofino [41]

Answer:

If two people have answered, you chose the one you want to give brainliest, and give them a crown on their answer.

Step-by-step explanation:

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3 years ago

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The swimsuit is on sale for 25% off its original price. If the original price was $58. What is the sale price?

sergiy2304 [10]

$58.00 \div 10 \times 2 \div 2 \div 2$

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3 years ago

Write an equation of the line with the given properties. Your answer should be written in standard form.

Vanyuwa [196]

Given:

The slope of the line is m=0.

The line passes through the point P(-9,-3).

To find:

The equation of the line in standard form.

Solution:

Standard form of a line is:

$Ax+By=C$

The slope intercept form of the line is

$y-y_1=m(x-x_1)$

Where, m is the slope and $(x_1,y_1)$ is the point on the line.

It is given that the slope of the line is 3 and it passes through the point (-9,-3), so the equation of the line is

$y-(-3)=0(x-(-9))$

$y+3=0$

$y=-3$

Therefore, the standard form of the given line is $y=-3$ .

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3 years ago

Analysis of an accident scene indicates a car was traveling at a velocity of 69.5 mph (31.1 m/s) along the positive x-axis at th

STatiana [176]

We can find the acceleration via

${v_f}^2-{v_i}^2=2a\Delta x$

We have

$\left(5.20\dfrac{\rm m}{\rm s}\right)^2-\left(31.1\dfrac{\rm m}{\rm s}\right)^2=2a(115\,\mathrm m)$

$\implies\boxed{a=-4.09\dfrac{\rm m}{\mathrm s^2}}$

Then by definition of average acceleration,

$a_{\rm ave}=\dfrac{v_f-v_i}t$

so that

$-4.09\dfrac{\rm m}{\mathrm s^2}=\dfrac{5.20\frac{\rm m}{\rm s}-31.1\frac{\rm m}{\rm s}}t$

$\implies\boxed{t=6.33\,\mathrm s}$

We alternatively could have found the time without knowing the acceleration. Since acceleration is constant, the average velocity is

$v_{\rm ave}=\dfrac{x_f-x_i}t=\dfrac{v_f+v_i}2$

Then

$\dfrac{115\,\rm m}t=\dfrac{5.20\frac{\rm m}{\rm s}+31.1\frac{\rm m}{\rm s}}2$

$\implies\boxed{t=6.33\,\mathrm s}$

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3 years ago