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boyakko [2]
3 years ago
7

A sarcomere stores calcium within the muscle cell.

Physics
1 answer:
professor190 [17]3 years ago
7 0
Sarcomere<span>The Sarcomere is the smallest functional unit of a myofibril (and also of the entire muscle) and contain the contractual elements between each pair of Z-discs.</span>
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The molecule arrangement of ice, water and steam are very different. _______ has the most ordered arrangement, ______ has the ne
marysya [2.9K]

Answer:

do you still need an answer

Explanation:

because if you are i could give it to you

3 0
4 years ago
A parallel-plate capacitor is charged and then is disconnected from the battery. By what factor does the stored energy change wh
andrew-mc [135]

Answer:

0.5

Explanation:

The energy of a charged capacitor is given by \frac{1}{2}QC where Q is the charge on it and C is its capacitance. The capacitance is defined, geometrically, as

\dfrac{\epsilon A}{d}

where \epsilon is a constant that is determined by the material between the plates, A is the area of the plates and d is the distance between them. It is then that the capacitance is linearly inversely proportional to the separation distance; as the distance increases, the capacitance reduces.

Because it is linear, when the separation distance is doubled, other factors remaining constant, the capacitance is halved. Because the capacitance is halved, the energy is halved.

Let's see the mathematics.

Initial capacitance, C_1 at initial separation, d_1

C_1=\dfrac{\epsilon A}{d_1}

If separation is doubled, separation becomes d_2=2d_1. Then the capacitance becomes

C_2=\dfrac{\epsilon A}{d_2}

C_2=\dfrac{\epsilon A}{2d_1}

C_2=0.5\dfrac{\epsilon A}{d_1}

C_2=0.5C_1

Initial energy, E_1=\frac{1}{2}QC_1

Final energy, E_2=\frac{1}{2}QC_2= \frac{1}{2}Q\times0.5C_1

E_2=0.5\times\frac{1}{2}QC_1=0.5E_1

Hence, \frac{E_2}{E_1}=0.5

5 0
3 years ago
What is the passengers velocity on the vertical drop of the tower of terror at Disney world if the distance for the drop is 50m,
andrey2020 [161]

Assuming constant acceleration due to gravity of a=9.8\,\dfrac{\mathrm m}{\mathrm s^2}, and assuming the passengers start at rest, so that v_0=0\,\dfrac{\mathrm m}{\mathrm s}, we have

v=v_0+at\implies v=\left(9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)(5.5\,\mathrm s)=53.9\,\dfrac{\mathrm m}{\mathrm s}

or 54 m/s if taking significant digits into account.

7 0
3 years ago
A 1000 kg satellite and a 2000 kg satellite follow exactly the same orbit around the earth. What is the ratio F1/F2 of the gravi
Tamiku [17]

Answer:

the <em>ratio F1/F2 = 1/2</em>

the <em>ratio a1/a2 = 1</em>

Explanation:

The force that both satellites experience is:

F1 = G M_e m1 / r²       and

F2 = G M_e m2 / r²

where

  • m1 is the mass of satellite 1
  • m2 is the mass of satellite 2
  • r is the orbital radius
  • M_e is the mass of Earth

Therefore,

F1/F2 = [G M_e m1 / r²] / [G M_e m2 / r²]

F1/F2 = [G M_e m1 / r²] × [r² / G M_e m2]

F1/F2 = m1/m2

F1/F2 = 1000/2000

<em>F1/F2 = 1/2</em>

The other force that the two satellites experience is the centripetal force. Therefore,

F1c = m1 v² / r    and

F2c = m2 v² / r

where

  • m1 is the mass of satellite 1
  • m2 is the mass of satellite 2
  • v is the orbital velocity
  • r is the orbital velocity

Thus,

a1 = v² / r ⇒ v² = r a1    and

a2 = v² / r ⇒ v² = r a2

Therefore,

F1c = m1 a1 r / r = m1 a1

F2c = m2 a2 r / r = m2 a2

In order for the satellites to stay in orbit, the gravitational force must equal the centripetal force. Thus,

F1 = F1c

G M_e m1 / r² = m1 a1

a1 = G M_e / r²

also

a2 = G M_e / r²

Thus,

a1/a2 = [G M_e / r²] / [G M_e / r²]

<em>a1/a2 = 1</em>

4 0
3 years ago
a ferry which runs at 12m/s in still water travels between towns a and b on a river which flows south at 9 m/s. the ferry leavs
Reil [10]

Answer:

= 15 m/s

Explanation:

Considering right side(west) as positive x-axis and south as negative y-axis.

velocity of boat in still water v_b=12\hat{i}

velocity of stream v_s=-9\hat{j}

now relative velocity of boat w.r.t. stream v_{b/s}=12\hat{i}+9\hat{j}

this velocity with which ac distance will be covered.

therefore magnitude of v_{b/s} =\sqrt{12^2+9^2}

= 15 m/s

6 0
3 years ago
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