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3 years ago

Three numbers have a mean of 12 and a mode of 9. What are the three numbers?

Mathematics

1 answer:

Oksanka [162]3 years ago

7 0

Answer:

The three numbers are : 9, 9 and 18

Step-by-step explanation:

Since the mean is 12 the sum of the three numbers must be 36. This is because:

(let the three numbers be x y and z)

(x+y+z)/3=12

(x+y+z)=12*3

(x+y+z)=36

And since the mode is 9 two of the numbers must be 9.

So to find the third number;

9+9+z=36

z=36-18

z=18

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Elza [17]

Answer:

x=20

Step-by-step explanation:

just use the pythagorean theorem!!

square 12 and 16 to get 144 and 256

add those together to get 400, and then just take the square root of 400 (which is 20)

this means that x=20!

hope this helps!! :)

6 0

3 years ago

Geometry help will give brainliest<br>my answer was wrong

rjkz [21]

Use tan
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3 years ago

The given box plots show the number of text messages Paul and Sally received each day on their cell phones.

zavuch27 [327]

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4 years ago

A bucket that weighs 6 lb and a rope of negligible weight are used to draw water from a well that is 80 ft deep. The bucket is f

zaharov [31]

Answer:

3200 ft-lb

Step-by-step explanation:

To answer this question, we need to find the force applied by the rope on the bucket at time $t$

At $t=0, the weight of the bucket is 6+36=42 \mathrm{lb}$

After $t$ seconds, the weight of the bucket is $42-0.15 t \mathrm{lb}$

Since the acceleration of the bucket is the force on the bucket by the rope is equal to the weight of the bucket.

If the upward direction is positive, the displacement after $t$ seconds is $x=1.5 t$

Since the well is 80 ft deep, the time to pull out the bucket is $\frac{80}{2}=40 \mathrm{~s}$

We are now ready to calculate the work done by the rope on the bucket.

Since the displacement and the force are in the same direction, we can write

$W=\int_{t=0}^{t=36} F d x$

Use $x=1.5 t$ and $F=42-0.15 t$

$W=\int_{0}^{36}(42-0.15 t)(1.5 d t)$

$=\int_{0}^{36} 63-0.225 t d t$

$=63 \cdot 36-0.2 \cdot 36^{2}-0=3200 \mathrm{ft} \cdot \mathrm{lb}$

$=\left[63 t-0.2 t^{2}\right]_{0}^{36}$

$W=3200 \mathrm{ft} \cdot \mathrm{lb}$

4 0

3 years ago

Square with side 4 is dilated by 7

Kazeer [188]

Answer:

196 in/cm/m²

Step-by-step explanation:

Given that the scale factor is a : b , then the area factor is a² : b² Here the scale factor is 1 : 7 , thus area scale factor is 1² : 7² = 1 : 49 That is the area of the dilated square is 49 times the original square. area of dilated square = 4 × 49 = 196 in/cm/m²

5 0

3 years ago