The distance of the road junction form Timpson is given as 21.57 miles.
<h3>We have to solve this using the Pythagoras theorem method</h3>
We have AT = 
√60² + 12² = 12√26
∠TMG = LN = 90 degrees
Therefore we have the system
When we cross multiply we would have to solve for TM
TM = 21.57 miles
Hence the distance of the road junction form Timpson is given as 21.57 miles.
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Answer:
7.39
Step-by-step explanation:
Answer:
x=3, y=-1
Step-by-step explanation:
We are already given an equation solved for x, making substitution much easier. We know x=4y+7, meaning we can put 4y+7 whenever we see x in the second equation
2x-6y=12
We substitute 4y+7 in place of x
2(4y+7)-6y=12
Now we only have one variable to work on, distribute the 2
8y+14-6y=12
Combine similar terms, 8y-6y=2y
2y+14=12
Subtract 14 from both sides
2y=-2
y=-1
Now we plug in -1 for y in the first equation to find x
x=4(-1)+7
x=-4+7
x=3
The answer for those are
320.544
489.6
Answer:
None! .7632 is smaller than 9.
Step-by-step explanation:
