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3 years ago

Help Meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Mathematics

1 answer:

MrMuchimi3 years ago

7 0

C definitely c hope this helps

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3 years ago

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Sergio [31]

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Will mark as Brainliest

OleMash [197]

Answer:

32in^2

Step-by-step explanation:

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3 years ago

Read 2 more answers

Emily practices piano for 2/3 of an hour on Monday and 1/2 hour on Wednesdays. How many hours does Emily spend practicing piano

Sergeu [11.5K]

Answer:

50 minutes

Step-by-step explanation:

Given:

$\bullet \ \ \text{Monday:} \ \dfrac{2}{3} \times \text{Hour}\\\\\bullet \ \text{Wednesday:} \ \dfrac{1}{2} \times \text{Hour}$

Since Emily only practiced on Monday and Wednesday, the sum of time on both days is the time Emily practiced on the piano for a week.

$\implies \text{Monday + Wednesday = Total time practiced on piano for a week}$

<u>Substitute the times in the equation</u>

$\implies (\dfrac{2}{3} \times \text{Hour}) + (\dfrac{1}{2} \times \text{Hour}) = \text{Total time practiced on piano for a week}$

<u>Simplify the equation</u>

$\implies (\dfrac{2}{3} \times 60 \ \text{minutes}) + (\dfrac{1}{2} \times 60 \ \text{minutes}) = \text{Total time practiced on piano for a week}$

$\implies (20 \ \text{minutes}) + (30 \ \text{minutes}) = \text{Total time practiced on piano for a week}$

$\implies \boxed{50 \ \text{minutes} = \text{Total time practiced on piano for a week}}$

4 0

2 years ago

Problem 2.191 A researcher receives 93 containers of oxygen. Of those containers, 20 have oxygen that is not ionized and the res

Ahat [919]

Answer:

Step-by-step explanation:

Given that there are 20 non ionized containers and 73 ionized containers

Two samples are drawn without replacement

a) the probability that the first one selected is not ionized= $\frac{20}{93} =0.215$

b) the probability that the second one selected is not ionized given that the first one was ionized

= When first one was ionized we got left over as 20 and 72

Hence = $\frac{20}{92} =0.217$

c) If with replacement left over 20 and 73 and hence prob = 0.215 as in part a

d) the probability that both are ionized= $\frac{73C2}{93C2} =0.614$

6 0

4 years ago