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algol13
3 years ago
7

Simplify

\sqrt{3} \times \sqrt{21} " alt=" \sqrt{3} \times \sqrt{21} " align="absmiddle" class="latex-formula">
Please Help​
Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
4 0

Answer:

3 times sq rt 7

jdjdhdmdhdkxnd

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Solve each literal equation for the given variable y=x+12;x
kakasveta [241]

Answer:

Step-by-step explanation:

x + 12 = y

x = y - 12

6 0
3 years ago
Assume that ∠A  is an acute angle. If sin A = 0.994, use a calculator to find the measure of ∠A to two decimal places.   The mea
Sedbober [7]
Basically, you are looking for the ARC SINE of .994 which is
 83.72 Degrees
You could also use an online calculator:
http://www.1728.org/trigcalc.htm


8 0
3 years ago
The scale of a map is 1cm:12 km. find the actual distance for 12cm
anzhelika [568]
This is simply a question about ratios. This ratio means that for every 1 cm on the map, there are 12 km in actuality. You can set this problem up in fractions:

1 cm           12 cm
--------   =   ----------
12 km             x

To solve for x, we cross-multiply, for the moment ignoring units. Remember, your answer will be in km.

1*x=12*12

x=144

If x=144, then for 12 cm, there are 144 km.


6 0
3 years ago
ANSWER ASAP!!!
mr_godi [17]

Answer:

c

Step-by-step explanation:

got it right on edjenuity

6 0
2 years ago
Question 12<br> With steps please
34kurt

Answer:\ \boxed{5^2}

\sqrt[n]{a}=a^\frac{1}{n}\\\\\text{therefore}\\\\\sqrt5=5^\frac{1}{2}\\----------------\\25=5^2\\----------------\\78,125=5^7\\----------------\\\text{use}\\\\a^n\cdot a^m=a^{n+m}\\\\\dfrac{a^n}{a^m}=a^{n-m}\\----------------\\\\\dfrac{\sqrt5\times78,125}{25\times5^{\frac{7}{2}}}=\dfrac{5^\frac{1}{2}\times5^7}{5^2\times5^\frac{7}{2}}=\dfrac{5^{\frac{1}{2}+7}}{5^{2+3\frac{1}{2}}}=\dfrac{5^{7\frac{1}{2}}}{5^{5\frac{1}{2}}}=5^{7\frac{1}{2}-5\frac{1}{2}}=\boxed{5^2}

6 0
3 years ago
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