Dissociation of NaCl in water is given as below,
NaCl ₍s₎ → Na⁺ ₍aq₎ + Cl⁻ ₍aq₎
According to this balanced equation the moles on RHS and LHS are as,
Moles on LHS,
NaCl ₍s₎ = 1 Mole
Moles on RHS,
Na⁺ ₍aq₎ = 1 Mole
Cl⁻ ₍aq₎ = 1 Mole
Result:
<span>When one mole of sodium chloride dissociates in water, it produces 2 Moles of Ions.</span>
Given that solubility product of AgCl = 1.8 X 10^-10
Dissociation of AgCl can be represented as follows,
AgCl(s) ↔ Ag+(ag) + Cl-(aq)
Let, [Ag+] = [Cl-] = S
∴Ksp = [Ag+][Cl-] = S^2
∴ S = √Ksp = √(1.8 X 10^-10) = 1.34 x 10^-5 mol/dm3
Now, Molarity of solution =

∴ 1.34 x 10^-5 =

∴ Weight of AgCl present in solution = 1.92 X 10^-3 g
Thus,
mass of AgCl that will dissolve in 1l water = 1.92 x 10^-3 g
I think it might be D or B
And my other two might be A or C
An c.ionic bond forms when a cation transfers its extra electron to an anion who needs it.
For example compound magnesium chloride (MgCl₂) has ionic bond (<span>the </span>electrostatic attraction<span> between oppositely charged </span><span>ions)</span>. Magnesium transfers two electrons (became positive cation) to chlorine (became negative anion).
1 lbs ----------- 0.453592 kg
123 lbs -------- ??
123 x 0.453592 / 1 => 55.7919 kg