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zhannawk [14.2K]
2 years ago
7

Assuming the reaction is at STP if 2.25 moles of Li are exposed to 3.25 moles of water, which is the limiting reactant?

Chemistry
1 answer:
crimeas [40]2 years ago
5 0

Answer: Lithium

Explanation:

The ratio for the reaction of Li and water is the same, but there are more moles of water than lithium. Therefore, lithium is the limiting reactant.

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In a polyatomic ion, the -ate ending indicates one ____ oxygen than the -ite ending.
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In a polyatomic ion, the ate ending indicates one more oxygen than the ite ending. D. more.
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________ are solutions containing ions that react with acids or bases to minimize their effects.
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<span>ions are solutions containing ions that react with acids or bases to minimize their effects. </span>
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A student wants to make a 0.150 M aqueous solution of silver (I) nitrate but only has 11.27 g of AgNO3. What volume of the 0.150
Usimov [2.4K]

Answer:

442.3 mL

Explanation:

Remember that Molarity is a measure of concentration in Chemistry and it's defined as the number of moles of the substance divided by liters of the solution:

M=\frac{Moles of substance X}{Volume of the solution}

Then, you can express 11.27 g of AgNO3 as moles of AgNO3 using the molar mass of the compound:

11.27 g AgNO_{3} *\frac{1 mole AgNO_{3}}{169.87 g AgNO_{3}} = 0.06634 moles AgNO_{3}

Then you can solve for the volume of the solution:

Volume of the solution=\frac{Moles of AgNO_{3}}{M} =\frac{0.06634 mol AgNO_{3}}{0.150 M} =0.4423 L = 442.3 mL

Hope it helps!

3 0
3 years ago
Nonrenewable energy sources come out of the ground as liquids, gases,
elixir [45]

Answer:

TRUE

Explanation:

Production of Hydrocarbons from Natural Gas is as stated below:

Natural gas liquids include propane, butane, pentane, hexane, and heptane, but not methane and not <u>always</u> ethane, (<em>may include it </em><em><u>sometimes</u></em><em>.</em>) s<em>ince these hydrocarbons need refrigeration to be liquefied.</em>

4 0
2 years ago
Calculate the standard entropy of vaporization of ethanol at its boiling point, 352 K. The standard molar enthalpy of vaporizati
Korvikt [17]

Answer : The correct option is, (b) +115 J/mol.K

Explanation :

Formula used :

\Delta S=\frac{\Delta H_{vap}}{T_b}

where,

\Delta S = change in entropy

\Delta H_{vap} = change in enthalpy of vaporization = 40.5 kJ/mol

T_b = boiling point temperature = 352 K

Now put all the given values in the above formula, we get:

\Delta S=\frac{\Delta H_{vap}}{T_b}

\Delta S=\frac{40.5kJ/mol}{352K}

\Delta S=115J/mol.K

Therefore, the standard entropy of vaporization of ethanol at its boiling point is +115 J/mol.K

8 0
3 years ago
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