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Kryger [21]
3 years ago
15

A piece of silver (Ag) metal weighing 194.3 g is placed in a graduated cylinder containing 242.0 mL of water. The volume of wate

r now reads 260.5 ml. From these data calculate the density of silver.
Chemistry
2 answers:
Gnesinka [82]3 years ago
7 0

Answer:

10.5027027 g/mL

Explanation:

The density is the result to divide the mass to the volume.

In this case, the volume which is occupeted for the piece of silver is the difference between the volume with the silver inside the cylinder containing minus the initial volume (only water).

V = 260.5mL - 242.0mL = 18.5 mL

The mass of silver is a data: M=194.3g

Density =  M/V ⇒ Density = 194.3g / 18.5mL

Density= 10.5027027 g/mL

mariarad [96]3 years ago
6 0

Answer: The density of silver metal will be 10.50g/ml[\tex]Explanation:Density is defined as the mass contained per unit volume.[tex]Density=\frac{mass}{Volume}

Given : Mass of silver = 194.3 grams

Volume of silver= volume of water displaced= 260.5-242.0=18.5mltex]Putting in the values we get:[tex]Density=\frac{194.3g}{18.5ml}=10.50g/ml/tex]Thus density of silver metal will be [tex]10.50g/ml

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First of all we will write the balance chemical equation.

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