This would decrease by 25 hope this helps !!
Answer:
copper
Explanation:
so for this you can work out the mass for both and compare
so mass = moles × mr
so mass of sodium = 1 × 23= 23 g
and mass of copper = 1 × 63.5= 63.5 g
so copper have more mass :)
The precipitation reaction of sodium nitrate and lead (II) chloride would not happen. No reaction will happen between these substances. Hope this answers the question. Have a nice day.
All the answers are on the actual periodic table. You should never be told to remember it so I think this is a recourse you are allowed to look at whilst doing your homework lol :) all the answers are written on it hope it helps
Answer: The value of
for the half-cell reaction is 0.222 V.
Explanation:
Equation for solubility equilibrium is as follows.

Its solubility product will be as follows.
![K_{sp} = [Ag^{+}][Cl^{-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BAg%5E%7B%2B%7D%5D%5BCl%5E%7B-%7D%5D)
Cell reaction for this equation is as follows.

Reduction half-reaction:
, 
Oxidation half-reaction:
,
= ?
Cell reaction: 
So, for this cell reaction the number of moles of electrons transferred are n = 1.
Solubility product, ![K_{sp} = [Ag^{+}][Cl^{-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BAg%5E%7B%2B%7D%5D%5BCl%5E%7B-%7D%5D)
= 
Therefore, according to the Nernst equation
At equilibrium,
= 0.00 V
Putting the given values into the above formula as follows.

= 
= 0.577 V
Hence, we will calculate the standard cell potential as follows.



= 0.222 V
Thus, we can conclude that value of
for the half-cell reaction is 0.222 V.