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bagirrra123 [75]
3 years ago
12

FeCl3 + 3NaOH → Fe(OH)3 + 3NaCl

Chemistry
2 answers:
bulgar [2K]3 years ago
6 0
<h3>Answer:</h3>

2.6299 g NaCl

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN} FeCl₃ + 3NaOH → Fe(OH)₃ + 3NaCl

[Given] 2.43306 g FeCl₃

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol FeCl₃ = 3 mol NaCl

Molar Mass of Fe - 55.85 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of Na - 22.99 g/mol

Molar Mass of FeCl₃ = 55.85 + 3(35.45) = 162.2 g/mol

Molar Mass of NaCl - 22.99 + 35.45 = 58.44 g/mol

<u>Step 3: Stoichiometry</u>

  1. Set up:                               \displaystyle 2.43306 \ g \ FeCl_3(\frac{1 \ mol \ FeCl_3}{162.2 \ g \ FeCl_3})(\frac{3 \ mol \ NaCl}{1 \ mol \ FeCl_3})(\frac{58.44 \ g \ NaCl}{1 \ mol \ NaCl})
  2. Multiply/Divide:                                                                                                \displaystyle 2.62986 \ g \ NaCl

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We need 5 sig figs (instructed).</em>

2.62986 g NaCl ≈ 2.6299 g NaCl

Romashka-Z-Leto [24]3 years ago
4 0

Answer:

2.6299

Explanation:

just did the quiz

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