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luda_lava [24]
3 years ago
7

Given the following equation: CH4 + 202 CO2 + 2H2O

Chemistry
2 answers:
trapecia [35]3 years ago
8 0

Answer:

Mass = 0.8 g

Explanation:

Given data:

Mass of oxygen = 3.2 g

Mass of CH₄ = ?

Solution:

Chemical equation:

CH₄ + 2O₂     →     CO₂ + 2H₂O

Number of moles of O₂:

Number of moles = mass/molar mass

Number of moles = 3.2 g/ 32 g/mol

Number of moles = 0.1 mol

Now we will compare the moles of CH₄ and O₂.

                         O₂          :       CH₄  

                           2          :          1

                         0.1         :        1/2 = 0.1 = 0.05

Mass of CH₄:

Mass = number of moles × molar mass

Mass = 0.05 mol ×  16 g/mol

Mass = 0.8 g

                 

lawyer [7]3 years ago
4 0

Answer:

0.8

Explanation:

Chunga

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3 years ago
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Mariulka [41]

Answer:

When the partially positive end of one water molecule is attracted to the partially negative end of another water molecule

Explanation:

6 0
3 years ago
What has the same number of valence electrons in the outermost shell?
algol [13]

Answer:

Groups

Explanation:

Elements with the same number of valence electrons are found in the same column(group) of the Periodic Table.

4 0
3 years ago
In order to study hydrogen halide decomposition, a researcher fills an evacuated 1.11 L flask with 0.822 mol of HI gas and allow
Elza [17]

Answer:

Kc = 168.0749

Explanation:

  •           2HI(g)     ↔    H2(g) + I2(g)

initial mol:   0.822               0          0

equil. mol: 2(0.822 - x)         x           x

∴ [ HI ]eq = 0.055 mol/L = 2(0.822 - x) / (1.11 L )

⇒ 1.644 - 2x = 0.055 * 1.11

⇒ 1.644 = 2x + 0.06105

⇒ 2x = 1.583

⇒ x = 0.7915 mol equilibrium

⇒ [ H2 ] eq = 0.7915mol / 1.11L = 0.7130 M = [ I2 ] eq

⇒ Kc = ([ H2 ] * [ I2 ]) / [ HI ]²

⇒ Kc = ( 0.7130² ) / ( 0.055² )

⇒ Kc = 168.0749

 

4 0
3 years ago
At a pressure of 19.95kPa, 35.8g of carbon dioxide at a temperature of 27.5C would result in what volume of gas?
adell [148]

Answer:

volume of gas=101.94L

Explanation:

Suppose given gas follows the ideality nature of gas

PV=nRT

n=35.8/44mol=0.814 mol

P=0.197atm

T=27.5C=300.5K

R=0.0821atm/mol/K

after putting all value we get,

V=101.94L

volume of gas=101.94L

3 0
3 years ago
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