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luda_lava [24]
3 years ago
7

Given the following equation: CH4 + 202 CO2 + 2H2O

Chemistry
2 answers:
trapecia [35]3 years ago
8 0

Answer:

Mass = 0.8 g

Explanation:

Given data:

Mass of oxygen = 3.2 g

Mass of CH₄ = ?

Solution:

Chemical equation:

CH₄ + 2O₂     →     CO₂ + 2H₂O

Number of moles of O₂:

Number of moles = mass/molar mass

Number of moles = 3.2 g/ 32 g/mol

Number of moles = 0.1 mol

Now we will compare the moles of CH₄ and O₂.

                         O₂          :       CH₄  

                           2          :          1

                         0.1         :        1/2 = 0.1 = 0.05

Mass of CH₄:

Mass = number of moles × molar mass

Mass = 0.05 mol ×  16 g/mol

Mass = 0.8 g

                 

lawyer [7]3 years ago
4 0

Answer:

0.8

Explanation:

Chunga

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Answer:

The volume of air at where the pressure and temperature are  52 kPa, -5.0 ºC is 3.64 m^3.

Explanation:

The combined gas equation is,

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T_1 = initial temperature of gas = 21.1^oC=273+21.1=294.1K

T_2 = final temperature of gas = -5.0^oC=273+(-5.0)=268 K

Now put all the given values in the above equation, we get:

\frac{104 kPa\times 2.0m^3}{294.1 K}=\frac{52 kPa\times V_2}{268 K}

V_2=3.64 m^3

The volume of air at where the pressure and temperature are  52 kPa, -5.0 ºC is 3.64 m^3.

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3 years ago
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<u>Explanation</u>:

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Answer:

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