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Cerrena [4.2K]
3 years ago
6

Help quick ! It’s due today so please . Thank you so much. I’ll Mark you branliest

Mathematics
2 answers:
raketka [301]3 years ago
6 0
Ok but they need the answer…
Anna11 [10]3 years ago
3 0

Answer:

YOU WOULD NEED TO USE THE TEACH METHOD TO SOLVE THIS QUESTION

Step-by-step explanation:

T: TOPIC SENTENCE

E: EVIDENCE

A: ANALYSIS

C: CLOSING SENTENCE

H: CHECK YOUR WORK

TRY THAT METHOD WITH EVERY PARAGRAPH

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150% of 48 as a percent
frosja888 [35]

Answer:

72, 150%

Step-by-step explanation:

8 0
4 years ago
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Could someone help me with another word problem fir math ! Points and brainlest!
Diano4ka-milaya [45]

Answer:

I think 15

Step-by-step explanation:

Because there are 3 in every 20 and 20 goes into 100 5 times and 5×3=15

8 0
3 years ago
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A bag contains 120 balls. The ratio of red to blue balls is 10:2
Alina [70]

Answer:

100 red balls and 20 blue balls.

Step-by-step explanation:

So to find out what you need to multiply the ratio by to get the answer, you add 10 and 2. That's 12. 120/12 is 10. 10:2 times 10 = 100: 20, so there are 100 red balls and 20 blue balls.

5 0
2 years ago
What type of polygon is shown?
VARVARA [1.3K]
Its a convex hexagon
6 0
3 years ago
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Sixty percent of the eligible voting residents of a certain community support the incumbent candidate. If eight of the residents
il63 [147K]

By the binomial theorem we know that

1 = (.4 + .6)^8 \\ = {8 \choose 0} (.4)^{8} (.6)^{0} + {8 \choose 1} (.4)^{7} (.6)^{1} +{8 \choose 2} (.4)^{6} (.6)^{2} + {8 \choose 3} (.4)^{5} (.6)^{3} + {8 \choose 4} (.4)^{4} (.6)^{4} \\ + \quad {8 \choose 5} (.4)^{3} (.6)^{5} + {8 \choose 6} (.4)^{2} (.6)^{6} + {8 \choose 7} (.4)^{1} (.6)^{7} + {8 \choose 8} (.4)^{0} (.6)^{8}

The probability that exactly 5 of 8 support the incumbent is the term

 {8 \choose 5} (.4)^{3} (.6)^{5}

So at least five of eight support is the sum of this term and beyond,

p={8 \choose 5} (.4)^{3} (.6)^{5} + {8 \choose 6} (.4)^{2} (.6)^{6} + {8 \choose 7} (.4)^{1} (.6)^{7} + {8 \choose 8} (.4)^{0} (.6)^{8}

No particularly easy way of calculating that except popping it into Wolfram Alpha which reports

p = \dfrac{ 46413}{78125}

Shouldn't half the terms work out to .6 ?  Interestingly it's not exactly .6 but pretty close at .594.

6 0
4 years ago
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