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Marina86 [1]
3 years ago
9

An industrial engineer is planning to test the claim that the mean cycle time of a particular assembly process is less than 10 m

inutes. She sets α = 0.05 and plans to take a SRS of 100 such processes and record the cycle time for each. If the true mean cycle time of the assembly process is 9.78 minutes the power of her test is 0.85. In all possible samples of size 100 she will:
Mathematics
1 answer:
Over [174]3 years ago
3 0

Answer:

Make a Type I error 15% of the time.

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>In all possible samples of size 100 she will:</em>

  1. <em>Make a Type II error 5% of the time</em>
  2. <em>Reject the null hypothesis 15% of the time</em>
  3. <em>Make a Type I error 5% of the time</em>
  4. <em>Fail to reject the null hypothesis 85% of the time</em>

Option 2 and 4 are both false because we can not estimate this probabilitites a priori.

Option 1.

The power of a test is defined as the conditional probability of rejecting the null hypothesis, given that the alternative hypothesis is true.

Then, the power of the test is complementary of the probability of failing to reject the null hypothesis, gicen that the alternative hypothesis is true. The last is the definition of the probability of a Type II error.

This means that a power of 0.85 implies a probability of (1-0.85)=0.15 of making a Type II error.

P(Type \,II\, error)=1-Power=1-0.85=0.15

The option 1 ("Make a Type II error 5% of the time") is not precise, so it is not correct.

Option 3

The significance level is 0.05. This is also the probability of making a Type I error.

The option 3 ("Make a Type I error 5% of the time") is correct.

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Ksju [112]
42 Ornaments- 28 Blue ornaments = 14 Red Ornaments
Ratio of Red to Blue 14:28 
Which can be simplified to 1:2 
7 0
3 years ago
The cows at the farm eat 5 3/5 hay everyday.The horses eat 1 5/6 as much as the cows. How bales of hay are the horses fed each d
Marina86 [1]

Answer:

13 2/9

Step-by-step explanation:

Cows eats=5 3/5 Hays everyday

Horses eats=1 5/6 as much as the cow

=1 5/6 of what the cow eat+5 3/5

=1 5/6 × 5 3/5 + 5 3/5

=11/6×28/6+28/6

= 308/36+28/6

=308+168/36

=476/36

=13 8/36

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5 0
3 years ago
Slope-rate of change- “if there were 12,000 in the Atlantic Ocean in 1950 and there are 3,600 dolphins today, what is the yearly
jasenka [17]

\bf \begin{array}{|cc|ll} \cline{1-2} \stackrel{x}{year}&\stackrel{y}{dolphins}\\ \cline{1-2} &\\ 1950&12000\\ 2018&3600 \\&\\ \cline{1-2} \end{array}~\hspace{5em}(\stackrel{x_1}{1950}~,~\stackrel{y_1}{12000})\qquad (\stackrel{x_2}{2018}~,~\stackrel{y_2}{3600}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{3600-12000}{2018-1950}\implies \cfrac{-8400}{68}~~\approx~~ \stackrel{\textit{rate of change}}{-123.53}


-8400/68 simplifies to to -2100/17,  dolphins/year, so 2100 less dolphins every 17 years.

and we can just divide those to get the decimal amount of -123.53, which means, 123.53  less dolphins every year.

of course, there's no such a thing as 0.53 of a dolphin, so, we can say "about" 123 less dolphins per year.

5 0
3 years ago
. The fourth grade class is donating 100 clothing items to charity. 63 hundredths of the items are sweaters and 0.20 of the item
inessss [21]

Answer: 17/100

Step-by-step explanation:

63/100 is sweaters and 20/100 is jeans and when you add them together you get 83/100. 100/100-83/100=17/100

6 0
2 years ago
Help pls you get 27 points
Trava [24]

Answer:

C. [-5] < [-3]   ||   D. [-4] < [-2]

Step-by-step explanation:

in A. 5 should be greater, > than -3

in B. 2 should be greater, > than -4

in C. its correct answer. true statement.

in D.  its correct answer. true statement.

5 0
2 years ago
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