Answer:
Step-by-step explanation:
-2(6+s) ≥ -15 -2s
step 1: first remove the parenthesis
-12 - 2s ≥ -15 -2s
step 2: add +12 to each side to combine like and unlike terms
-12 - 2s + 12 ≥ 15 - 2s +12
= -2s ≥ 27 - 2s
step 3: then add +2s to each side to obtain unknown sides
-2s + 2s ≥ 27 -2s + 2s
0 ≥ 27 + 0
Answer: No solution
In Summary
Step 1 Eliminate fractions by multiplying all terms by the least common denominator of all fractions.
Step 2 Simplify by combining like terms on each side of the inequality.
Step 3 Add or subtract quantities to obtain the unknown on one side and the numbers on the other.
Step 4 Divide each term of the inequality by the coefficient of the unknown. If the coefficient is positive, the inequality will remain the same. If the coefficient is negative, the inequality will be reversed.
Step 5 Check your answer.
in domain problems here is two things to keep in mind:
1. Square root or the root of any even power cannot be negative. Also look for things like x^1/4 since that is just the 4th root of x.
2. Denominator cannot be 0.
For such problems you can try plugging the numbers in and see which one of them lead to the 2 points mentioned above, and use elimination by glance to select the options that make more sense to plug in first.
Answer:
The three quadratic equations are;
x² + 3 = 0
x² + 2·x + 1 = 0
x² + 3·x + 2 = 0
Step-by-step explanation:
1) A quadratic equation with no real solution is one with an imaginary solution such as one with a negative square root
We can write the quadratic equation as follows;
x² + 3 = 0
∴ x = √(-3) = √(-1) ×√3 = i·√(3)
Therefore, the equation f(x) = x² + 3, has no real root at f(x) = 0
2) A quadratic that has 1 real root is of the form;
(x + 1)² = 0
The root of the equation is x = -1 from (x + 1) = ((-1) + 1)² = 0²
Which gives;
(x + 1)² = (x + 1)·(x + 1) = x² + 2·x + 1 = 0
Therefore, the quadratic (x + 1)² = 0 has only one real root
3) A quadratic that has 2 real root is of the form;
(x + 1)·(x + 2) = 0
x² + x + 2·x + 2 = 0
x² + 3·x + 2 = 0
Therefore, the three quadratic equations are;
x² + 3 = 0
x² + 2·x + 1 = 0
x² + 3·x + 2 = 0
4 packs x 8= 32. Safeway is selling 32 packs of gum
12/(5+10)=m/10
4/5=m/10
m=8