Kinetic energy = (1/2) (mass) (speed²).
A Physicist in the canoe, or on a raft floating downriver next to the canoe, will say that the canoe's kinetic energy is zero.
A Physicist on the riverbank, watching the canoe drift by at 1 m/s, will say that its kinetic energy is 9 Joules.
They're both correct.
The ball only accelerates during the brief time that the club is in contact
with it. After it leaves the club face, it takes off at a constant speed.
If it accelerates at 20 m/s² during the hit, then
Force = (mass) x (acceleration) = (0.2kg) x (20 m/s²) = <em>4 newtons</em> .
Answer:
12.5 m/s
Explanation:
The motion of the hammer is a free fall motion, so a uniformly accelerated motion, therefore we can use the following suvat equation:
![v^2-u^2=2as](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as)
Where, taking downward as positive direction, we have:
s = 8 m is the displacement of the hammer
u = 0 is the initial velocity (it is dropped from rest)
v is the final velocity
is the acceleration of gravity
Solving the equation for v, we find the final velocity:
![v=\sqrt{u^2+2as}=\sqrt{0+2(9.8)(8)}=12.5 m/s](https://tex.z-dn.net/?f=v%3D%5Csqrt%7Bu%5E2%2B2as%7D%3D%5Csqrt%7B0%2B2%289.8%29%288%29%7D%3D12.5%20m%2Fs)
So, the final speed is 12.5 m/s.
<u>26mm</u> is the thinnest thickness of oil that will brightly reflect the light.
What is wavelength ?
The distance over which a periodic wave's shape repeats is known as the wavelength in physics. It is a property of both traveling waves and standing waves as well as other spatial wave patterns. It is the distance between two successive corresponding locations of the same phase on the wave, such as two nearby crests, troughs, or zero crossings. The spatial frequency is the reciprocal of wavelength. The Greek letter lambda () is frequently used to represent wavelength. The term wavelength is also occasionally used to refer to modulated waves, their sinusoidal envelopes, or waves created by the interference of several sinusoids.
To learn more about wavelength visit:
brainly.com/question/16051869
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Answer:
V=14.9 m/s
Explanation:
In order to solve this problem, we are going to use the formulas of parabolic motion.
The velocity X-component of the ball is given by:
![Vx=V*cos(\alpha)\\Vx=15.7*cos(31^o)=13.5m/s](https://tex.z-dn.net/?f=Vx%3DV%2Acos%28%5Calpha%29%5C%5CVx%3D15.7%2Acos%2831%5Eo%29%3D13.5m%2Fs)
The motion on the X axis is a constant velocity motion so:
![t=\frac{d}{Vx}\\t=\frac{20.0}{13.5}=1.48s](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bd%7D%7BVx%7D%5C%5Ct%3D%5Cfrac%7B20.0%7D%7B13.5%7D%3D1.48s)
The whole trajectory of the ball takes 1.48 seconds
We know that:
![Vy=Voy+(a)*t\\Vy=15.7*sin(31^o)+(-9.8)*(1.48)=-6.42m/s](https://tex.z-dn.net/?f=Vy%3DVoy%2B%28a%29%2At%5C%5CVy%3D15.7%2Asin%2831%5Eo%29%2B%28-9.8%29%2A%281.48%29%3D-6.42m%2Fs)
Knowing the X and Y components of the velocity, we can calculate its magnitude by:
![V=\sqrt{Vx^2+Vy^2} \\V=\sqrt{(13.5)^2+(-6.42)^2}=14.9m/s](https://tex.z-dn.net/?f=V%3D%5Csqrt%7BVx%5E2%2BVy%5E2%7D%20%5C%5CV%3D%5Csqrt%7B%2813.5%29%5E2%2B%28-6.42%29%5E2%7D%3D14.9m%2Fs)