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3 years ago

How has the jester archetype evolved over thr years?

Physics

1 answer:

Murrr4er [49]3 years ago

7 0

LakalakalalamLlalaa hahahaha

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The launching catapult of the aircraft carrier gives the jet fighter a constant acceleration of 59 m/s2 from rest relative to th

irina [24]

Answer:

Explanation:

We shall find the final velocity of aircraft with respect to aircraft carrier using the following relation.

v² = u² + 2as

v² = 0² + 2 x 59 x 97

v² = 11446

v = 107 m /s

velocity of aircraft carrier = 1.852 x 26 = 48.152 km/h

= 48.152 x 1000 / (60 x 60) m/s

= 13.37 m /s

This velocity of aircraft carrier will be added to the velocity of aircraft .

So absolute velocity of aircraft = 107 m /s + 13.37 m/s

= 120.37 m/s

7 0

3 years ago

The range of audible frequencies is from about 20.0 hz to 2.00×104 hz . what is range of the wavelengths of audible sound in air

TiliK225 [7]

The wavelength is related to the frequency by the relationship:
$\lambda= \frac{v}{f}$
where v is the wave speed and f is its frequency.

The speed of sound in air is v=344 m/s. The lowest frequency is f=20.0 Hz, so the corresponding wavelength is
$\lambda_1 = \frac{v}{f_1}= \frac{344 m/s}{20.0 Hz}=17.2 m$
The highest frequency is $f_2 = 2.00 \cdot 10^4 Hz$ , so the corresponding wavelength is
$\lambda_2 = \frac{v}{f_2}= \frac{344 m/s}{2.00 \cdot 10^4 Hz}=0.017 m$

Therefore, the range of wavelengths of audible sound in air is
[0.017 m - 17.2 m]

4 0

3 years ago

Question 7 (4 points) (01.02 MC) The gravitational strength at the poles is greater than the gravitational strength at the equat

musickatia [10]

I think it’s A but not really sure

4 0

4 years ago

Three resistors are connected in series to a 42.1 V battery: R1 = 2.96 Ω, R2 = 7.48 Ω and R3 = 7.42 Ω. Now, as R3 heats up, its

LuckyWell [14K]

Answer:

dP/dt = 26.12 W/s

Explanation:

First, we need to find the value of dt at the instant when R₃ becomes 91.7 Ω. Therefore, we use:

dR₃/dt = 0.552 Ω/s

where,

dR₃ = Change in value of resistance 3 = 91.7 Ω - 7.42 Ω = 84.28 Ω

dt = time interval = ?

Therefore,

84.28 Ω = (0.552 Ω/s)(dt)

dt = (84.28 Ω)/(0.552 Ω/s)

dt = 152.68 s

Now, we find change in power (dP):

dP = V(R₁ + R₂ + dR₃)

dP = (42.1 V)(2.96 Ω + 7.48 Ω + 84.28 Ω)

dP = 3987.71 W

Dividing by dt:

dP/dt = 3987.71 W/152.68 s

7 0

4 years ago

Can one of yall help???

Art [367]

1,200 x 3.0 = 3600N

8 0

3 years ago

Read 2 more answers