Answer:
  a =( -0.32 i ^ - 2,697 j ^)  m/s²
Explanation:
This problem is an exercise of movement in two dimensions, the best way to solve it is to decompose the terms and work each axis independently.
 Break down the speeds in two moments
initial
   v₀ₓ = v₀ cos θ
   v₀ₓ = 5.25 cos 35.5
 v₀ₓ = 4.27 m / s
    = v₀ sin θ
 = v₀ sin θ
   = 5.25 sin35.5
= 5.25 sin35.5
  = 3.05 m / s
 = 3.05 m / s
Final
 vₓ = 6.03 cos (-56.7)
 vₓ = 3.31 m / s
  = v₀ sin θ
 = v₀ sin θ
  = 6.03 sin (-56.7)
 = 6.03 sin (-56.7)
  = -5.04 m / s
 = -5.04 m / s
Having the speeds and the time, we can use the definition of average acceleration that is the change of speed in the time order
     a = ( - v₀) /t
 - v₀) /t
     aₓ = (3.31 -4.27)/3 
     aₓ = -0.32 m/s²
      = (-5.04-3.05)/3
 = (-5.04-3.05)/3
     =  -2.697 m/s²
 =  -2.697 m/s²
 
        
             
        
        
        
The reason as to why the substage condenser does not need to be included in computing the magnification and the only component needed is the ocular lens and the objective lenses is because the condenser is only responsible for gathering light and it does not contribute with the magnification of the object under the microscope.
        
                    
             
        
        
        
Answer:
by using formula F=ma which is m stand for mass a stand for acceleration. so 500kg × 2 ms^-2
 
        
                    
             
        
        
        
The monomer of glucose makes up all carbohydrates
        
             
        
        
        
     Considering the unknown resistence as R and using the Ohm's First Law, we have:
 
      The equivalent resistence is given by the resistor series with the lamp resistence.

If you notice any mistake in my english, please let me know, because i am not native.