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elena-s [515]
3 years ago
11

What are the advantages and Disadvantages of using Circuit Breakers Instead of Fuses

Physics
2 answers:
Inessa [10]3 years ago
7 0

Answer:

The benefits are defined throughout the section described according to the particular context.

Explanation:

  • Just before it completes its function, users should substitute a fuse, although circuit breakers work through a trigger where you essentially restart or reboot.
  • Fuses become composed of such a lump of material (metal) that can explode when enough electric current is passed through everything, disturbing another circuit successfully therefore stopping the equipment from hitting another power outage.
lesya [120]3 years ago
4 0

Answer:

Explanation:

Circuit breaker is an automatic electrical  switch which cuts the power when there is surge in current.

Advantages of Circuit breaker

  • They are more reliable i.e. they are not replaced frequently
  • Efficient and easy to safeguard electrical appliance

Disadvantage of Circuit breaker

  • They are less sensitive than fuses i.e. fuses are much faster than circuit breaker.

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A 60 cm diameter wheel accelerates from rest at a rate of 7 rad/s2. After the wheel has undergone 14 rotations, what is the radi
Mamont248 [21]

Answer:

a=368.97\ m/s^2

Explanation:

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Initial angular velocity, \omega=0

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Rotation, \theta=14\ rotation=14\times 2\pi =87.96\ rad

Let t is the time. Using second equation of kinematics can be calculated using time.

\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\\t=\sqrt{\dfrac{2\theta}{\alpha }} \\\\t=\sqrt{\dfrac{2\times 87.96}{7}} \\\\t=5.01\ s

Let \omega_f is the final angular velocity and a is the radial component of acceleration.

\omega_f=\omega_i+\alpha t\\\\\omega_f=0+7\times 5.01\\\\\omega_f=35.07\ rad/s

Radial component of acceleration,

a=\omega_f^2r\\\\a=(35.07)^2\times 0.3\\\\a=368.97\ m/s^2

So, the required acceleration on the edge of the wheel is 368.97\ m/s^2.

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3 years ago
Is there any machine that is 100% efficient? why?why not
denis-greek [22]

Answer:

No, it's not there.

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For a machine to be 100% efficient, it has to be with an output which is equal to its input. But machines have an out put less than an input, hence efficiency below 100%.

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