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2 years ago

What are the advantages and Disadvantages of using Circuit Breakers Instead of Fuses

Physics

2 answers:

Inessa [10]2 years ago

7 0

Answer:

The benefits are defined throughout the section described according to the particular context.

Explanation:

Just before it completes its function, users should substitute a fuse, although circuit breakers work through a trigger where you essentially restart or reboot.
Fuses become composed of such a lump of material (metal) that can explode when enough electric current is passed through everything, disturbing another circuit successfully therefore stopping the equipment from hitting another power outage.

lesya [120]2 years ago

4 0

Answer:

Explanation:

Circuit breaker is an automatic electrical switch which cuts the power when there is surge in current.

Advantages of Circuit breaker

They are more reliable i.e. they are not replaced frequently
Efficient and easy to safeguard electrical appliance

Disadvantage of Circuit breaker

They are less sensitive than fuses i.e. fuses are much faster than circuit breaker.

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In an experiment, you find the mass of a cart to be 250 grams. What is the mass of the cart in kilograms?

gizmo_the_mogwai [7]

It should be 0.25kg because you converter from g to kg and since 1g<1kg so you move the decimal to the left

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3 years ago

Read 2 more answers

A particle of mass m collides with a second particle of mass m. Before the collision, the first particle is moving in the x-dire

oee [108]

Answer:

a) v, v

b) 2mv^2

c) Elastic collion

Explanation:

(a) The velocity of the second particle after the collision is (v2x,v2y)=(v,−v). From momentum conservation in x-direction

Here x, y represent direction.They are not variable. 1 and 2 represent before and after.

2vm=v1xm+v2xm, we find v1x=v.

From momentum conservation in y-direction

0 =v1ym+v2ym, we findv1y=v.

(b) By energy conservation principle

Before: K=1/2m(2v)^2=2mv^2.

After: K=1/2m(v^2(1x)+v^2(1y))+12m(v22x+v22y)=2mv^2

6 0

3 years ago

A meter stick is suspended vertically at a pivot point 22 cm from the top end. It is rotated on the pivot until it is horizontal

suter [353]

Answer:

5.82812 rad/s

Explanation:

L = Length of meter stick = 1 m = 100 cm

$m_c$ = The center of mass of the stick = $\frac{L}{2}-0.22=0.5-0.22=0.28\ m$

$\omega$ = Angular velocity

Moment of inertia of the system is given by

$I=I_c+mr^2\\\Rightarrow I=\frac{mL^2}{12}+mr^2\\\Rightarrow I=\frac{m1^2}{12}+m0.28^2\\\Rightarrow I=m(\frac{1}{12}+0.0784)$

As the energy in the system is conserved

$mgh=I\frac{\omega^2}{2}\\\Rightarrow mgh=m(\frac{1}{12}+0.0784)\frac{\omega^2}{2}\\\Rightarrow gh=(\frac{1}{12}+0.0784)\frac{\omega^2}{2}\\\Rightarrow \omega=\sqrt{\frac{2gh}{\frac{1}{12}+0.0784}}\\\Rightarrow \omega=\sqrt{\frac{2\times 9.81\times 0.28}{\frac{1}{12}+0.0784}}\\\Rightarrow \omega=5.82812\ rad/s$