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2 years ago

11

What are the advantages and Disadvantages of using Circuit Breakers Instead of Fuses

2 answers:

Inessa [10]2 years ago

7 0

Answer:

The benefits are defined throughout the section described according to the particular context.

Explanation:

Just before it completes its function, users should substitute a fuse, although circuit breakers work through a trigger where you essentially restart or reboot.
Fuses become composed of such a lump of material (metal) that can explode when enough electric current is passed through everything, disturbing another circuit successfully therefore stopping the equipment from hitting another power outage.

lesya [120]2 years ago

4 0

Answer:

Explanation:

Circuit breaker is an automatic electrical switch which cuts the power when there is surge in current.

Advantages of Circuit breaker

They are more reliable i.e. they are not replaced frequently
Efficient and easy to safeguard electrical appliance

Disadvantage of Circuit breaker

They are less sensitive than fuses i.e. fuses are much faster than circuit breaker.

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Diego is trying to lift a piano to the second floor of his house. Diego uses a pulley system and gives a big lift to the piano.T

andreyandreev [35.5K]

Answer:he to

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2 years ago

series RC circuit is built with a 15 kΩ resistor and a parallel-plate capacitor with 18-cm-diameter electrodes. A 18 V, 36 kHz s

andre [41]

Answer:

$d=1.84\ mm$

Explanation:

<u>Capacitance</u>

A two parallel-plate capacitor has a capacitance of

$\displaystyle C=\frac{\epsilon_o A}{d}$

where

$\epsilon_o=8.85\cdot 10^{-12}\ F/m$

A = area of the plates = $\pi r^2$

d = separation of the plates

$\displaystyle d=\frac{\epsilon_o A}{C}=\frac{\epsilon_o \pi r^2}{C}$

We need to compute C. We'll use the circuit parameters for that. The reactance of a capacitor is given by

$\displaystyle X_c=\frac{1}{wC}$

where w is the angular frequency

$w=2\pi f=2\pi \cdot 36000=226194.67\ rad/s$

Solving for C

$\displaystyle C=\frac{1}{wX_c}$

The reactance can be found knowing the total impedance of the circuit:

$Z^2=R^2+X_c^2$

Where R is the resistance, $R=15 K\Omega=15000\Omega$ . Solving for Xc

$X_c^2=Z^2-R^2$

The magnitude of the impedance is computed as the ratio of the rms voltage and rms current

$\displaystyle Z=\frac{V}{I}$

The rms current is the peak current Ip divided by $\sqrt{2}$ , thus

$\displaystyle Z=\frac{\sqrt{2}V}{I_p}$

$I_p=0.65\ mA/1000=0.00065\ A$

Now collect formulas

$\displaystyle X_c^2=Z^2-R^2=\left(\frac{\sqrt{2}V}{I_p}\right)^2-R^2$

Or, equivalently

$\displaystyle X_c=\sqrt{\frac{2V^2}{I_p^2}-R^2}$

$\displaystyle X_c=\sqrt{\frac{2\cdot 18^2}{0.00065^2}-15000^2}$

$X_c=36176.34\ \Omega$

The capacitance is now

$\displaystyle C=\frac{1}{226194.67\cdot 36176.34}=1.22\cdot 10^{-10}\ F$

The radius of the plates is

$r=18\ cm/2=9 \ cm = 0.09 \ m$

The separation between the plates is

$\displaystyle d=\frac{8.85\cdot 10^{-12} \cdot \pi\cdot 0.09^2}{1.22\cdot 10^{-10}}$

$d=0.00184\ m$

$\boxed{d=1.84\ mm}$

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3 years ago

Most split-brain surgeries are preformed on ___________. A. neurology patients B. intractable epilepsy patients C. abnormal psyc

Alexandra [31]

B. Intractable epilepsy patients

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2 years ago

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A wave with a high frequency generally has a _____.

il63 [147K]

High frequency = D, short wavelength

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3 years ago

Please help me solve this and give an explanation

Arlecino [84]

Answer:

6.5

Explanation:

Because 1.5+5=6.5

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2 years ago