A horizontal force is applied to an object making it run with a constant velocity across a surface.
Answer:
It is the same reason that the distance by road is not the same as the distance "as the crow flies." The two vectors are often not aligned so that the magnitudes both add to directly to the distance from the origin (or the tail of the first vector).
For example, suppose you walk two segments of 1 mile each. If you walk east in both cases, you end up 2 miles east of where you started. (The sum of the vectors is the sum of their magnitudes.)
If you walk east 1 mile and north 1 mile, you end up about 1.4 miles from where you started, not 2 miles. The second "vector" did not add directly to the distance from your starting point.
If you walk east 1 mile, then west 1 mile, you end up exactly where you started. The sum of the vectors is zero, but the sum of their magnitudes is still 2 miles.
Explanation:
Answer:
Work is done by the heart on the blood during this time is 0.04 J
Explanation:
Given :
Mass of blood pumped, m = 80 g = 0.08 kg
Initial speed of the blood, u = 0 m/s
Final speed of the blood, v = 1 m/s
Initial kinetic energy of blood is determine by the relation:
Final kinetic energy of blood is determine by the relation:
Applying work-energy theorem,
Work done = Change in kinetic energy
W = E₂ - E₁
Substitute the suitable values in the above equation.
W = 0.04 J
Answer:
Explanation:
ΔE = Δm × c^2
where,
ΔE = change in energy released with respect to change in mass
= 1.554 × 10^3 kJ
= 1.554 × 10^6 J
Δm = change in mass
c = the speed of light.
= 3 × 10^8 m/s
Equation of the reaction:
2H2 + O2 --> 2H2O
Mass change in this process, Δm = 1.554 × 10^6/(3 × 10^8)^2
= 1.727 × 10^-11 kg
The change in mass calculated from Einstein equation is small that its effect on formation of product will be negligible. Hence, law of conservation of mass holds correct for chemical reactions.
Answer:
Torque is 140.4 N-m.
Explanation:
Mass of the gymnast, m = 53 kg
Vertical force acting on the gymnast, F = 1080 N
Distance, r = 0.13 m behind the center of mass during a forward somersault. We need to find the torque generated about the center of mass. The force is acting behind the center of mass. F = -1080 N
Torque is given by :
So, the torque generated about the center of mass is 140.4 N-m.