Explanation:
It is given that,
Voltage of the battery, V = 12 V
Current, I = 100 ampere-hours
Energy stored is given by the product of power and time taken. So,
P is the power,
P = 1200 watts
This power can be used for 1 hour or 3600 seconds
Energy,
E = 4320000 J
So, the energy stored in this battery is 4320000 J. Hence, this is the required solution.