All categories

3 years ago

Choose the correct domain of the function in interval notation.

Mathematics

2 answers:

neonofarm [45]3 years ago

8 0

Answer:

domain : (-∞,∞)

Step-by-step explanation:

Domain is the set of x values for which the function is defined

To find domain we check the x value for which the function is undefined

In the give graph , the graph is continuous and smooth.

There is no break in the graph.

We have graph for all values of x

So domain is set of all real values

domain : (-∞,∞)

kari74 [83]3 years ago

3 0

The domain of a function is where the x of the function starts and finishes , but as that function doenst have an end or beginning, its domain is a) from negative infinity to infinity

You might be interested in

There are 10,000 dolphins swarming for food. For each single dolphin on the surface ,20 are below the water. How many dolphins a

Maru [420]

Answer:500 on top of the water and 9,500 below

Step-by-step explanation:

6 0

3 years ago

In a certain Algebra 2 class of 29 students, 7 of them play basketball and 24 of them play baseball. There are 3 students who pl

antiseptic1488 [7]

Answer:

$\frac{5}{29}$

Step-by-step explanation:

Let $n(A)$ represent students playing basketball, $n(B)$ represent students playing baseball.

Then, $n(A)=7$ , $n(B)=24$

Let $n(S)$ be the total number of students. So, $n(S)=29$ .

Now,

$P(A)=\frac{n(A)}{n(S)}=\frac{7}{29}$

$P(B)=\frac{n(B)}{n(S)}=\frac{24}{29}$

3 students play neither of the sport. So, students playing either of the two sports is given as:

$n(A\cup B)=n(S)-3\\n(A\cup B)=29-3=26$

∴ $P(A\cup B)=\frac{n(A\cup B)}{n(S)}=\frac{26}{29}$

From the probability addition theorem,

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Where, $P(A\cap B)$ is the probability that a student chosen randomly from the class plays both basketball and baseball.

Plug in all the values and solve for $P(A\cap B)$ . This gives,

$\frac{26}{29}=\frac{7}{29}+\frac{24}{29}+P(A\cap B)\\\\\frac{26}{29}=\frac{7+24}{29}+P(A\cap B)\\\\\frac{26}{29}=\frac{31}{29}+P(A\cap B)\\\\P(A\cap B=\frac{31}{29}-\frac{26}{29}\\\\P(A\cap B=\frac{31-26}{29}=\frac{5}{29}$