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Alenkinab [10]
3 years ago
7

50 people entered a fishing contest over 3 days to see who could catch the most fish.

Mathematics
2 answers:
tamaranim1 [39]3 years ago
6 0

Answer:

5,175 fish

Step-by-step explanation:

To figure out the total you have to add all the fish together.

Day 1: 750 + 300 + 250 = 1,300 fish were caught on Day 1

Day 2: 720 + 455 + 400 + 50 = 1,625 were caught on Day 2

Day 3: 2,250 were caught on Day 3

Then, add those three numbers

1,300 + 1,625 + 2,250 = 5,175

dybincka [34]3 years ago
3 0

Answer:5,175

Step-by-step explanation:

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r² = 0.5652  < 0.7 therefore, the correlation between the variables does not imply causation

Step-by-step explanation:

The data points are;

X,          Y

0.7,       1.11

21.9,     3.69

18,         4

16.7,      3.21

18,         3.7

13.8,      1.42

18,          4

13.8,      1.42

15.5,      3.92

16.7,       3.21

The correlation between the values is given by the relation

Y =   b·X + a

b = \dfrac{N\sum XY - \left (\sum X  \right )\left (\sum Y  \right )}{N\sum X^{2} - \left (\sum X  \right )^{2}}

a = \dfrac{\sum Y - b\sum X}{N}

Where;

N = 10

∑XY = 499.354

∑X = 153.1

∑Y = 29.68

∑Y² = 100.546

∑X² = 2631.01

(∑ X)² = 23439.6

(∑ Y)² = 880.902

From which we have;

b = \dfrac{10 \times 499.354 -153.1 \times 29.68}{10 \times 2631.01 - 23439.6} = 0.1566

a = \dfrac{29.68 - 0.1566 \times 153.1}{10} = 0.5704

r = \dfrac{N\sum XY - \left (\sum X  \right )\left (\sum Y  \right )}{\sqrt{\left [N\sum X^{2} - \left (\sum X  \right )^{2} \right ]\times \left [N\sum Y^{2} - \left (\sum Y  \right )^{2} \right ]}}

r = \dfrac{10 \times 499.354 -153.1 \times 29.68}{\sqrt{\left (10 \times 2631.01 - 23439.6  \right )\times \left (10 \times 100.546- 880.902\right )}  } = 0.7518

r² = 0.5652  which is less than 0.7 therefore, there is a weak relationship between the variables, and it does not imply causation.

7 0
3 years ago
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