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3 years ago

What is the common differenice for this arithmetic sequence?

Mathematics

2 answers:

yaroslaw [1]3 years ago

8 0

Answer:

The answer is D.

Step-by-step explanation:

The difference between each term is 4.

-2 - (-6) = 4

2 - (-2) = 4

6 - 2 = 4

10 - 6 = 4

Yuki888 [10]3 years ago

5 0

d. 4

here, -2-(-6)= -2+6=4

2-(-2)= 2+2=4

6- 2 = 4

10-6 = 4

so the common difference of them is 4.

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Step-by-step explanation:

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3 years ago

If M is the set of all square of integers that are less than 100 and N is the set of all positive odd numbers that are under 15,

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A set is simply the group of numbers.

The set of M and N are: $M = \{1,4,9,16,25,36,49,64,81\}$ and $N= \{1,3,5,7,9,11,13\}$ .
The set of M n N is: $M\ n\ N = \{1,9\}$ .
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(a) The set of M and N

Given that:

M = squares of integers less than 100

N = Positive odd numbers less than 15

So, we have:

$M = \{1,4,9,16,25,36,49,64,81\}$

$N= \{1,3,5,7,9,11,13\}$

(b) M n N and M u N

M n N is the set of common elements between sets M and N.

So, we have:

$M\ n\ N = \{1,9\}$

M u N is the set of all elements in sets M and N.

So, we have:

$M\ u\ N = \{1,3,4,5,7,9,11,13,16,25,36,49,64,81\}$

Read more about sets at:

brainly.com/question/2332158

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2 years ago

Male and female high school students reported how many hours they worked each week in summer jobs. The data is represented in th

mihalych1998 [28]

Question:

1. The females worked less than the males, and the female median is close to Q1.

2. There is a high data value that causes the data set to be asymmetrical for the males.

3. There are significant outliers at the high ends of both the males and the females.

4. Both graphs have the required quartiles.

Answer:

The correct option is;

1. The females worked less than the males, and the female median is close to Q1

Step-by-step explanation:

Based on the given data, we have;

For males

Minimum = 0

Q1 = 1

Median or Q2 = 20

Q3 = 25

Maximum = 50

For females;

Minimum = 0

Q1 = 5

Median or Q2 = 6

Q3 = 10

Maximum = 18

Therefore, the values of data that affect the statistical measures of spread and center are that

The females worked less than the males as such the statistical data for the females have less variability than the males in terms of interquartile range

Also the female median is very close to Q1, therefore it affects the definition of a measure of center.

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3 years ago