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notsponge [240]
3 years ago
10

1 4/7 _______- 15/ 21​

Mathematics
1 answer:
Sati [7]3 years ago
3 0

Answer: -11/5

Step-by-step explanation:

\frac{11}{7}÷\frac{-15}{21}

-\frac{11}{7}× \frac{21}{15}

-11×\frac{3}{15}

-11 × \frac{1}{5}

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The area of a rectangle is 27 m^2 , and the length of the rectangle is 3 m less than twice the width. Find the dimensions of the
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Let L be the length of the rectangle and W be the width. In the problem it is given that L=2W-3. It is also given that the area LW=27. Substituting in the length in terms of width, we have W(2W-3)=27 \\ 2W^2-3W-27=0 \\ (2W-9)(W+3)=0. Using the zero product property, 2W-9=0 \text{ or } W+3=0. Solving these we get the width W=4.5 \text{ or } -3. However, it doesn't make sense for the width to be negative, so the width must be \boxed{4.5 \text{ m}}. From that we can tell the length L=2(4.5)-3=\boxed{6 \text{ m}}. 
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CALC!! Please help me. For which pair of functions f(x) and g(x) below will the limit as x goes to infinity of the product of f
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First limit:
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Discrete R.V. Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are
Tom [10]

Answer:

a) p=0.2

b) probability of passing is 0.01696

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c) The expected value of correct questions is 1.2

Step-by-step explanation:

a) Since each question has 5 options, all of them equally likely, and only one correct answer, then the probability of having a correct answer is 1/5 = 0.2.

b) Let X be the number of correct answers. We will model this situation by considering X as a binomial random variable with a success probability of p=0.2 and having n=6 samples. We have the following for k=0,1,2,3,4,5,6

P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k} = \binom{6}{k}0.2^{k}(0.8)^{6-k}.

Recall that \binom{n}{k}= \frac{n!}{k!(n-k)!} In this case, the student passes if X is at least four correct questions, then

P(X\geq 4) = P(X=4)+P(X=5)+P(X=6)=\binom{6}{4}0.2^{4}(0.8)^{6-4}+\binom{6}{5}0.2^{5}(0.8)^{6-5}+\binom{6}{6}0.2^{6}(0.8)^{6-6}= 0.01696

c)The expected value of a binomial random variable with parameters n and p is E[X] = np. IN our case, n=6 and p =0.2. Then the expected value of correct answers is 6\cdot 0.2 = 1.2

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3 years ago
3.14 times 16 divided by 3
AleksAgata [21]

Answer:

The answer is 16.746667

Step-by-step explanation:

1) Simplify 3.14 × 16 to 50.24.

50.24 \div 3

2) Simplify 50.24 ÷ 3 to 16.746667.

16.746667

<u>Therefor</u><u>. </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>16.746667.</u>

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It means not to get too invested in details or to become so invested in something that you can’t focus on anything else.
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