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barxatty [35]
3 years ago
12

Aluminum hydroxide is insoluble in pure water but dissolves in a solution of sodium hydroxide because: Select the correct answer

below: hydroxide ions neutralize the Al3 ion, a Lewis acid aluminum participates in an acid-base reaction in the presence of sodium hydroxide the excess of hydroxide ions pushes the equilibrium toward further dissolution of Al(OH)3 aluminum forms a complex ion with excess hydroxide
Chemistry
1 answer:
kkurt [141]3 years ago
5 0

Answer:

aluminum forms a complex ion with excess hydroxide

Explanation:

Complex formation accounts for the dissolution of certain compounds. For instance,reaction of aluminum and sodium hydroxide yields insoluble aluminum hydroxide as follows;

Al(s) + 3NaOH(aq) -----> Al(OH)3(s) +Na(s)

However, in excess NaOH, the solid aluminum hydroxide dissolves as due to the formation of a complex Al(OH)4^- in the solution.

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<span>2NH4Cl(s)+Ba(OH)2⋅8H2O(s)→2NH3(aq)+BaCl2(aq)+10H2O(l)

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