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Art [367]
3 years ago
12

The radius of a circle is 2 feet. What is the circle's area?

Mathematics
2 answers:
Ksju [112]3 years ago
6 0

Answer:

Step-by-step explanation:

radius squared multiplied by pi = area

2 squared = 4

3.14 x 4 = 12.56

Area= 12.56 feet squared

ExtremeBDS [4]3 years ago
4 0

Answer:

It is 12.57 ft^2.

Step-by-step explanation:

Use the formula A=πr2

Pi is about 3.14.

Do r^2 first to get 2^2=4.

4*3.14=12.566 and you can round up the decimal.

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Explain whether the graph represents a function.
aleksley [76]

Answer:

The vertical line test can be used to determine whether a graph represents a function. ... If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because that x value has more than one output. A function has only one output value for each input value.

8 0
2 years ago
A manufacturer makes three types of screws. Type A comes in a bulk pack of 1000 screws. Type B comes in a bulk pack of 500 screw
Tpy6a [65]

Answer:

Step-by-step explanation:

Given that a manufacturer makes three types of screws

Type             A        B           C Total

   

Pack         1000 500   800  

P for flaw 0.001 0.03 0.005  

Pack*p                 1 15                    4     20

a) Expected total number of defective screws = 20

b) For one pack each no of defective screws =20

Hence for 5 expected number number of packs form each should be 1/3

8 0
3 years ago
Need help on this math problem!!!
Colt1911 [192]

Answer:

(fof^{-1})(x)=x

Step-by-step explanation:

Composition of two functions f(x) and g(x) is represented by,

(fog)(x) = f[g(x)]

If a function is,

f(x) = (-6x - 8)² [where x ≤ -\frac{8}{6}]

Another function is the inverse of f(x),

f^{-1}(x)=-\frac{\sqrt{x}+8}{6}

Now composite function of these functions will be,

(fof^{-1})(x)=f[f^{-1}(x)]

                  = [-6(\frac{\sqrt{x}+8}{6})-8]^{2}

                  = [-\sqrt{x}+8-8]^2

                  = (-\sqrt{x})^2

                  = x

Therefore, (fof^{-1})(x)=x

4 0
3 years ago
Written as a simplified polynomial in standard form, what is the result when
kompoz [17]

2x-8 - (2x+7)^2\\\\=2x-8 -(4x^2 + 2\cdot 2x \cdot 7 + 7^2)\\\\=2x-8-(4x^2 + 28x +49)\\\\=2x - 8 -4x^2-28x -49\\\\=-4x^2 -26x -57\\\\

8 0
2 years ago
if you add the digits in a two-digit number and multiply the sum by 7, you get the original number. If you reverse the digits in
ANTONII [103]
Let m the tens digit and n the ones
the Original number is 10m+n
7(m+n) =10m+n
7m+7n=10m+n
6n=3m

Reversing the number 10n+m
10n+m=18+n+m
9n=18
n=2

6n=3m
6(2)=3m
3m=12
m=4
the number is 10m+n=10(4)+2=42
4 0
3 years ago
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