Let's say you are playing a coin-tossing game with a friend. You toss the same coin 500 times, and 400 times it comes up heads.
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Using the t-distribution, as we have the standard deviation for the sample, it is found that there is a significant difference between the wait times for the two populations.
<h3>What are the hypothesis tested?</h3>At the null hypothesis, we test if there is no difference, that is:
At the alternative hypothesis, it is tested if there is difference, that is:
For each sample, we have that:
For the distribution of differences, we have that:
It is given by:
In which is the value tested at the null hypothesis.
Hence:
Considering a one-tailed test, as stated in the exercise, with 100 - 1 = 99 df, using a t-distribution calculator, the p-value is of 0.014.
Since the p-value is less than the significance level of 0.05, it is found that there is a significant difference between the wait times for the two populations.
More can be learned about the t-distribution at brainly.com/question/16313918
Answer:
BC = 3 units
Step-by-step explanation:
Given points:
- A = (2, -2)
- B = (-4, -4)
- C = (-4, -1)
- D = (-2, 3)
- E = (1, 3)
- F = (2, 5)
<u>Plot the points</u> on the coordinate plane (x, y) and connect them in alphabetical order with straight lines (see attached).
From visual inspection of the <u>drawn polygon</u>, we can see that the length of BC is 3 units.
It is fairly simple to calculate the length of BC without plotting the points.
As points B and C have the same x-value, this means that the distance between them is simply the difference between their y-values.
⇒ distance = |-4 - (-1)| = |-3| = 3 units
