Answer:
30/pi cm
Step-by-step explanation:
2×pi×r =60
r = 60/2×pi =30/pi
Answer:
4' x 2' x 1'
Step-by-step explanation:
Collins' cube has a volume of that is the length of any side, x, cubed: Vol = x^3. Since his box has 8^3, we can say that x = 2. <u>[2^3 = 8]</u>
Amil's box has one side that is 2x. That side would be 2*2 = 4 feet. His volume is also 8 ft^3. Amil's box also has a volume of 8 ft^3.
His box dimensions are therefore: (4)(X)(Y) = 8 ft^3 , where X and Y are whole-number dimensions for the other 2 dimensions of his box.
(4)(X)(Y) = 8 ft^3
X*Y = 2
The only combination of whole numbers for which this this would work is 1 and 2.
Amil's box is 4' x 2' x 1' or 8 ft^3
F(x) - g(x)
becomes
(3x + 2) - (x - 3)
which is
3x + 2 - x + 3
then add like terms
2x + 5
so f(x) - g(x) = 2x + 5
and it's domain should be all real numbers
1) -16 = v - 14
Add 14 to both sides.
v = -2
2) -2n = -22
Divide both sides by -2.
n = 11
3) 25 = b + 7
Subtract 7 from both sides.
b = 18
