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AfilCa [17]
3 years ago
14

Carboxylic acids and alcohols react via dehydration and condensation to produce a/an _______ and water.

Chemistry
1 answer:
avanturin [10]3 years ago
4 0

Answer:

ester

Explanation:

Carboxylic acids and alcohols react in the presence of strong acid to produce an ester and water. The two carbon chains come together, which is the condensation, and then water is generated, which is dehydration. The resulting compound is an ester.

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This science of classifying organisms is called?
Verdich [7]

The classifying of organisms is called "Taxonomy" or the second option. Taxonomy mainly takes place with organisms although it could be used to classify anything. Taxonomy consists of a graph with eight categories all used to classify a living organism.

Hope this helps!

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3 years ago
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Which condition will decrease the rate of reaction between excess magnesium and hydrochloric acid?
tekilochka [14]

Answer:

B

Explanation:

The four factors that increase the rate of the reaction:

1.Concentration of the reactants

2.Size of the particles

3.Temperature

4.Catalyst

4 0
3 years ago
Dehydrohalogenation of 1-chloro-1-methylcyclopropane affords two alkenes (A and B) as products.
UNO [17]

Explanation:

Dehydrohalogenation reactions occurs as elimination reactions through the following mechanism:

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Step 2: The electrons from the broken hydrogen‐carbon bond are attracted toward the slightly positive carbon (carbocation) atom attached to the chlorine atom. As these electrons approach the second carbon, the halogen atom breaks free.

However, elimination will be slower in the exit of Hydrogen atom at the C2 and C3 because of the steric hindrance by the methyl group.

Elimination of the hydrogen from the methyl group is easier.

Thus, the major product will A

4 0
3 years ago
A buffer is prepared by adding 150mL of 0.50 M NH3 to 250mL of 0.50 M NH4NO3. What is the pH of the final solution? (Kb for NH3
Juli2301 [7.4K]

From the calculations, the pH of the final solution is 9.04.

<h3>What is the pH of the buffer?</h3>

We can use the Henderson Hasselbach equation to obtain the final pH of the solution in terms of the pKb and the base concentration.

Number of moles of salt = 250/1000 L * 0.5 M = 0.125 moles

Number of moles of base = 150/1000 L * 0.5 M = 0.075 moles

Total volume of solution = 250ml + 150ml = 400ml or 0.4 L

Molarity of base = 0.075 moles/ 0.4 L = 0.1875 M

Molarity of salt = 0.125 moles/ 0.4 L = 0.3125 M

pOH = pKb + log[salt/base]

pKb = -log(1.8 x 10^-5) = 4.74

pOH = 4.74 + log[0.3125/0.1875 ]

pOH = 4.96

pH = 14- 4.96

pH = 9.04

Learn more about pH:brainly.com/question/15289741

#SPJ1

5 0
2 years ago
Answer Question
vovangra [49]

Answer:

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4. July 16, 1969

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