There are two N≡N bonds and three H–H bonds are in reactants.
Given:
The reaction between nitrogen gas and hydrogen gas.

To find:
Bonds on the reactant side
Solution:

Reactants in the reaction = 
The bond between nitrogen atoms in single
molecule = N≡N (triple bond)
Then in two
molecules = 2 N≡N (triple bonds)
The bond between hydrogen atoms in single
molecule = H-H (single bond)
Then in three
molecules = 3 H-H (single bonds)
Product in the reaction =
The bonds between nitrogen and hydrogen atoms in single
molecule = 3 N-H (single bond)
Then in two
molecules = 6 N-H (single bonds)
So, there are two N≡N bonds and three H–H bonds are in reactants.
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Whereas ionic bonds join metals to non-metals, metallic bonding joins a bulk of metal atoms. ... Sodium metal is therefore written as Na, not Na+. ... Both of these factors increase the strength of the bond still further. ... Heat capacity: This is explained by the ability of free electrons to move about the solid.
Chemical because the propane has stored chemical energy which is being released and a by-product of that propane is heat or themal energy.
1. First, move the decimal place until you have a number between 1 and 10. If you keep moving the decimal point to the right in 0.0000073 you will get 7.3.
2. Next, count how many places you moved the decimal point.
Yes, they are right.Very good hand writing! You did a very great job on showing your work.