Write the ions present in the solution of cuso4. express your answers as chemical formulas separated by a comma. identify all of the phases in your answers.
2 answers:
Copper Sulfate (CuSO4) compound is basically comprised of Copper (II) ion and Sulfate ion. Ions are C<span>u2</span>+ and S<span>O4 2</span><span>−</span>.<em>ANSWER:</em> <em>Cu 2+ and SO4 2- </em>
Answer: The ions which are present in the solution of are , both in aqueous state.
Explanation: When is dissolved in water, it forms an aqueous solution. The solution contains two ions, both in aqueous states.
Equation follows:
Ions that are present in the solution of are
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Answer:
"0.60 g " is the appropriate solution.
Explanation:
The given values are:
Volume of base,
= 30 ml
Molarity of base,
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Molar mass of acid,
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As we know,
⇒
On substituting the values, we get
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hence,
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On substituting the values, we get
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Explanation:
01: 5.3316+6.87+37.48
02: 12.2016+37.48
03: 49.6816
04: 49.68
Answer: 49.68 (Decimals: 2; Significant Figures: 4)
HOPE THIS HELPS..