IV

Mathematics

1 answer:

Wewaii [24]3 years ago

5 0

Answer:

1. 648

2. 81

Step-by-step explanation:

6 * 6 * 6 * 3 = 648

3 * 3 * 3 * 3 = 81

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Ill mark brainliest!!

Anastasy [175]

Answer:

$60

Step-by-step explanation:

So from the question, we need to find the fixed amount for the tv's. So we have to make an equation, and don't forget to add the extended warranties:

11(x + 25) = 935

x will represent a tv, and the 25 is the extended warranty for a tv, since the questions states 11 tv's with warranties is 935, the equation will look like that. Now lets slove:

11(x + 25) = 935

multiply

11x + 275 = 935

subtract 275 from both sides

11x = 660

divide both sides by 11

x = 60, each tv is $60

4 0

3 years ago

What is a polynomial?

Alex777 [14]

Answer:

Now, I ain't tryin' to sound mean or standoff-ish but I'm pretty sure Wikipedia could answer this question for you

3 0

4 years ago

I need help with part b. I feel like there’s a catch, I want to do the first derivative test, however, I feel like there is a be

Sladkaya [172]

Answer:

The fifth degree Taylor polynomial of g(x) is increasing around x=-1

Step-by-step explanation:

Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:

$P_5(x)=g(-1)+g'(-1)\,(x+1)+g"(-1)\, \frac{(x+1)^2}{2!} +g^{(3)}(-1)\, \frac{(x+1)^3}{3!} + g^{(4)}(-1)\, \frac{(x+1)^4}{4!} +g^{(5)}(-1)\, \frac{(x+1)^5}{5!}$

and when you do its derivative:

1) the constant term renders zero,

2) the following term (term of order 1, the linear term) renders: $g'(-1)\,(1)$ since the derivative of (x+1) is one,

3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero

Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is: $g'(-1)= 7$ as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1