I am sure it is C because it is similar to A=p+pi.
<u>L</u><u>a</u><u>w</u><u> </u><u>o</u><u>f</u><u> </u><u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u>
![\displaystyle \large{ {a}^{ - n} = \frac{1}{ {a}^{n} } }](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%7B%20%7Ba%7D%5E%7B%20-%20n%7D%20%20%3D%20%20%5Cfrac%7B1%7D%7B%20%7Ba%7D%5E%7Bn%7D%20%7D%20%7D)
Compare the terms.
![\displaystyle \large{ {a}^{ - n} = {( - 2)}^{ - 3} }](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%7B%20%7Ba%7D%5E%7B%20-%20n%7D%20%20%3D%20%20%20%7B%28%20-%202%29%7D%5E%7B%20-%203%7D%20%7D)
Therefore, a = -2 and n = 3. From the law of exponent above, we receive:
![\displaystyle \large{ {( - 2)}^{ - 3} = \frac{1}{ {( - 2)}^{ 3} } }](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%7B%20%7B%28%20-%202%29%7D%5E%7B%20-%203%7D%20%20%3D%20%20%5Cfrac%7B1%7D%7B%20%7B%28%20-%202%29%7D%5E%7B%203%7D%20%7D%20%7D)
<u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u><u> </u><u>D</u><u>e</u><u>f</u><u>.</u> (For cubic)
![\displaystyle \large{ {a}^{3} = a \times a \times a }](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%7B%20%7Ba%7D%5E%7B3%7D%20%20%3D%20a%20%5Ctimes%20a%20%5Ctimes%20a%20%7D)
Factor (-2)^3 out.
![\displaystyle \large{ {( - 2)}^{ - 3} = \frac{1}{( - 2) \times ( - 2) \times ( - 2)}}](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%7B%20%7B%28%20-%202%29%7D%5E%7B%20-%203%7D%20%20%3D%20%20%5Cfrac%7B1%7D%7B%28%20-%202%29%20%5Ctimes%20%28%20-%202%29%20%5Ctimes%20%28%20-%202%29%7D%7D)
(-2) • (-2) = 4 | Negative × Negative = Positive.
![\displaystyle \large{ {( - 2)}^{ - 3} = \frac{1}{4 \times ( - 2)}}](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%7B%20%7B%28%20-%202%29%7D%5E%7B%20-%203%7D%20%20%3D%20%20%5Cfrac%7B1%7D%7B4%20%5Ctimes%20%28%20-%202%29%7D%7D)
4 • (-2) = -8 | Negative Multiply Positive = Negative.
![\displaystyle \large{ {( - 2)}^{ - 3} = \frac{1}{ - 8}}](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%7B%20%7B%28%20-%202%29%7D%5E%7B%20-%203%7D%20%20%3D%20%20%5Cfrac%7B1%7D%7B%20%20-%208%7D%7D)
If either denominator or numerator is in negative, it is the best to write in the middle or between numerator and denominators.
Hence,
![\displaystyle \large \boxed{ {( - 2)}^{ - 3} = - \frac{1}{ 8}}](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%20%5Cboxed%7B%20%7B%28%20-%202%29%7D%5E%7B%20-%203%7D%20%20%3D%20%20-%20%20%5Cfrac%7B1%7D%7B%20%208%7D%7D)
The answer is - 1 / 8
-1 is the answer ur looking for
5/10+1/10=6/10, they are equivalent since the denominator is the same :)