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HACTEHA [7]
3 years ago
11

7 1/2 divided by 3/4 =?

Mathematics
2 answers:
vaieri [72.5K]3 years ago
4 0

Answer:

7 1/2 divided by 3/4 is 10

Step-by-step explanation:

10

Brainiest please and thank you

nika2105 [10]3 years ago
3 0
10 i'm pretty sure sorry if i'm wrong
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This season, the probability that the Yankees will win a game is 0.6 and the probability that the Yankees will score 5 or more r
juin [17]

Answer:

Since this season, the probability that the Yankees will win a game is 0.6 The probability that the Yankees will lose when they score 5 or more runs is 19.2%.

Step-by-step explanation:

Since this season, the probability that the Yankees will win a game is 0.6 and the probability that the Yankees will score 5 or more runs in a game is 0.48, and he probability that the Yankees lose and score fewer than 5 runs is 0.33, To determine what is the probability that the Yankees will lose when they score 5 or more runs, the following calculation must be performed:

(1 - 0.6) x 0.48 = X

0.40 x 0.48 = X

0.192 = X

0.192 x 100 = 19.2

Therefore, the probability that the Yankees will lose when they score 5 or more runs is 19.2%.

8 0
3 years ago
Find the area of the composite figure.
irinina [24]

Answer:

Step-by-step explanation:

84

8 0
3 years ago
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What is the exponet of 10×10
Ivanshal [37]
The exponent of 10x10 is 100

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3 years ago
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An electronic product contains 40 integrated circuits. The probability that any integrated circuit is defective is 0.01, and the
neonofarm [45]

Answer:

There is a 33.10% probability that there is at least one defective integrated circuit.

Step-by-step explanation:

For either integrated circuit, there are only two possible outcomes. Either they are defective, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem

The electonic product contains 40 integrated circuits, so n = 40.

The probability that any integrated circuit is defective is 0.01, so \pi = 0.01

What is the probability that there is at least one defective integrated circuit?

Either there is at least one defective integrated circuit, that is probability P(X > 0), or there are no defective integrated circuits, that is probability P(X = 0). The sum of these probabilities is decimal 1. We want to find P(X>0).

P(X > 0) + P(X = 0) = 1

P(X > 0) = 1 - P(X = 0)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{40,0}.(0.01)^{0}.(0.99)^{40} = 0.6690

P(X > 0) = 1 - P(X = 0) = 1 - 0.6690 = 0.3310

There is a 33.10% probability that there is at least one defective integrated circuit.

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3 years ago
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7 I think

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